- #1
Yankel
- 395
- 0
Hello
I have a system of equations with the question "for which values of a the system has: a single solution, no solution and infinite number of solutions". In addition, I have some solution, and I need to find the mistake in the solution, I need some help with it...
So, for which values of a, the next system:
2x+y=1
4x+ay+z=0
3y+az=2
has a single solution, no solution and infinite number of solutions ?
View attachment 434
if a=2, the matrix has proportional rows (r2 and r3), and we get infinite number of solutions. However, if we set a=2 in the original system, there is a single solution.
Where is the mistake ?
Thanks !
I have a system of equations with the question "for which values of a the system has: a single solution, no solution and infinite number of solutions". In addition, I have some solution, and I need to find the mistake in the solution, I need some help with it...
So, for which values of a, the next system:
2x+y=1
4x+ay+z=0
3y+az=2
has a single solution, no solution and infinite number of solutions ?
View attachment 434
if a=2, the matrix has proportional rows (r2 and r3), and we get infinite number of solutions. However, if we set a=2 in the original system, there is a single solution.
Where is the mistake ?
Thanks !