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ajmCane22
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Homework Statement
The electric field at the point x = 10.0 cm and y = 0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x = 20.0 cm and y = 0 the electric field points in the positive x direction with a magnitude of 20.0 N/C. Assume that this electric field is produced by a single, point charge.
(a) Find the location of the point charge.
(b) Find the sign and magnitude of its charge.
The Attempt at a Solution
10 =q/4piε(d+10)^2
20 = q/4piε(d)^2
E is more at x=20 , so q must be -ve, and situated beyond x=20
dividing both eqn , we get
20/10 = d^2 + 100+ 20d/ d^2
solving the quadratic eqn , we get
d= 10±10√2
d= 24.14cm
put d= 24.14 in any above formula,
we get q= -0.13nC
Both answers are incorrect. I've gone to two different tutors and neither could help. Please help