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hydrocarbon
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The mass of the moon is 7.35*10^22Kg. At some point between Earth and the moon, the force of Earth's gravitational attraction on an object is canceled by the moon's force of gravitational attraction. If the distance between Earth and the moon (centre to centre) is 3.84*10^5 Km, calculate where this will occur, relative to earth.
required: r1
analysis: Fge=Fgm
therefore: (6.67*10^-11)(5.98*10^24)/(6.38*10^6)^2 = (6.67*10^-11)(7.35*10^22)/r^2
(5.98*10^24)(3.84*10^8)/(6.38*10^6)^2(7.35*10^22)= r^2
I got 282m which is clearly wrong can i please get some assistance with the steps? thank you very much
required: r1
analysis: Fge=Fgm
therefore: (6.67*10^-11)(5.98*10^24)/(6.38*10^6)^2 = (6.67*10^-11)(7.35*10^22)/r^2
(5.98*10^24)(3.84*10^8)/(6.38*10^6)^2(7.35*10^22)= r^2
I got 282m which is clearly wrong can i please get some assistance with the steps? thank you very much