- #1
Marcin H
- 306
- 6
Homework Statement
Homework Equations
V=IR
KVL/KCL
The Attempt at a Solution
I am stuck on part E of this problem. This looks like a valid circuit, but I am struggling with KVL/KCL to prove it.
First can I say that the voltage across the 1 ohm resistor is 6V because it is in parallel with the 6V battery? But wouldn't that mean that the voltage across the 2 ohm is also 6V? I'm not too sure how the current source there would affect that. Can I combine the current source with the 2 ohm resistor to make it into a battery and then use kvl? Right now I am trying loops for the left side and the right side and the whole thing and I am not getting anywhere. Can I assign a ground at the bottom of the middle node and try using node voltage method?
Left loop: 6V = i(1) --> i=6A? But that doesn't seem right.
The other loops I'm not too sure about because I am not sure if my logic with the voltage is correct. If it is then I would use that to try finding the KCL for the other loops.