- #1
mathdad
- 1,283
- 1
I found the following problem in Section 1.3 of my Precalculus textbook by David Cohen.
Factor x^6 - y^6 as a difference of squares and then as a difference of cubes.
1. Which method is easier and why?
2. Can someone get me started?
Factor x^6 - y^6 as a difference of squares and then as a difference of cubes.
1. Which method is easier and why?
2. Can someone get me started?