- #1
Yankel
- 395
- 0
a. every set of n linearly independent vectors are basis of a vector space with dimension n
b. An invertible matrix is necessarily diagonalizable
they both seems wrong to me, but only one suppose to be.
'a' sounds wrong because the n vectors must also span the vector space
and 'b' because I don't see the relation between invertible and diagonalizable
b. An invertible matrix is necessarily diagonalizable
they both seems wrong to me, but only one suppose to be.
'a' sounds wrong because the n vectors must also span the vector space
and 'b' because I don't see the relation between invertible and diagonalizable