Which should I use to prove this?

  • Thread starter Outrageous
  • Start date
In summary: The question itself is asking for a summary of the conversation, not a solution to the problem. So, in summary, the conversation involves discussing the Maxwell equations and determining the constant volume version of the equation Tds= du +pdv.
  • #1
Outrageous
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0
(∂s/∂P) at constant volume =1/T ×(∂u/∂T)at constant volume × (∂T/∂P) at constant volume

s(P,v)
Tds= du +pdv
h= u + pv
h(P,v)
u(P,v)
or other formula?
How am I going to choose ? Please guide

Thank
 
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  • #2
Outrageous said:
(∂s/∂P) at constant volume =1/T ×(∂u/∂T)at constant volume × (∂T/∂P) at constant volume

s(P,v)
Tds= du +pdv
h= u + pv
h(P,v)
u(P,v)
or other formula?
I'm not expert on gas theory, so I'll just treat this as an algebraic question.
Of those 'formulae', only two are equations. One of those two involves h, not mentioned anywhere else. So that leaves Tds= du +pdv as the only candidate.
What would the constant volume version of that equation look like?
 
  • #3
haruspex said:
I'm not expert on gas theory, so I'll just treat this as an algebraic question.
Of those 'formulae', only two are equations. One of those two involves h, not mentioned anywhere else. So that leaves Tds= du +pdv as the only candidate.
What would the constant volume version of that equation look like?

The others also can become equation like s is function of v and p
So ∂s=(∂s/∂p)dp + (∂s/∂v)dv
Then h=u + pv , can be dh= du + Pdv + vdp
This is all just dealing with mathematics , please teach me how to choose
Do you mean why did I put constant volume there? It means by keeping volume constant then only differentiate.
Thank
 
  • #4
Outrageous said:
(∂s/∂P) at constant volume =1/T ×(∂u/∂T)at constant volume × (∂T/∂P) at constant volume

s(P,v)
Tds= du +pdv
h= u + pv
h(P,v)
u(P,v)
or other formula?
How am I going to choose ? Please guide

Thank

Have you considered using the Maxwell relations?

BiP
 
  • #5
Outrageous said:
Do you mean why did I put constant volume there?
No, I mean take this equation: Tds= du +pdv
and turn it into an equation involving partial derivatives, v being constant.
 
  • #6
Bipolarity said:
Have you considered using the Maxwell relations?

BiP

haruspex said:
No, I mean take this equation: Tds= du +pdv
and turn it into an equation involving partial derivatives, v being constant.

I am not really understand what is Maxwell ,
I only can get (∂s/∂P) at constant volume = (1/T)(∂h/∂P)constant volume -(v/T)
 
  • #7
Outrageous said:
I only can get (∂s/∂P) at constant volume = (1/T)(∂h/∂P)constant volume -(v/T)
Please post your working to get that.
 
  • #8
Trial
 

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  • #9
This first , only that second deriavative
 

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  • #10
You need to follow BiP's advice and familurize yourself with the derivation and application of the Maxwell equations.
 

FAQ: Which should I use to prove this?

Which should I use to prove this: experiments or data analysis?

It depends on the nature of the question you are trying to answer. If you are trying to test a hypothesis or determine cause and effect, experiments may be more appropriate. However, if you are trying to analyze patterns or relationships in existing data, data analysis may be more suitable.

Can I use both experiments and data analysis to prove my point?

Yes, it is possible to use both methods to support your argument. This can provide a more comprehensive and well-supported conclusion.

How do I know if my experiments or data analysis are valid?

Valid experiments and data analysis should follow scientific principles and methods, have controls to eliminate bias, and use appropriate statistical analysis. It is also important to consider the reliability and accuracy of your data.

Is one method more reliable than the other?

Both experiments and data analysis can be reliable if conducted properly. However, the level of reliability may vary depending on the specific methods used and the quality of the data.

What are some common mistakes to avoid when using experiments or data analysis to prove something?

Some common mistakes include drawing conclusions from insufficient or biased data, misinterpreting statistical results, and not considering other factors that may affect the outcome. It is important to carefully design and conduct experiments or data analysis and to critically evaluate the results.

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