- #1
jeff1evesque
- 312
- 0
Does anyone know why a phasor consists of the magnitude of a voltage multiplied with a sinusoid? For instance,
[tex]
V_Scos(\omega t + \theta)
[/tex]
I am searching all over the web, and cannot find a general explanation why. I've found some incomplete mathematical proof showing the following:
[tex] Ae^{j \theta} = V = V_Scos(\omega t + \theta) [/tex]
but this doesn't explain the general concept.
Thanks so much,
JL
[tex]
V_Scos(\omega t + \theta)
[/tex]
I am searching all over the web, and cannot find a general explanation why. I've found some incomplete mathematical proof showing the following:
[tex] Ae^{j \theta} = V = V_Scos(\omega t + \theta) [/tex]
but this doesn't explain the general concept.
Thanks so much,
JL