Why Are -2+i and i the Only Complex Solutions?

In summary, the given equation contains complex numbers and variables, and when graphed on Mathematica online, the solutions are represented as points in the complex plane. The points -2+i and i are the complex solutions where the graph intersects the x-axis, while the points on the boundary of the circle (x+1)^2 + (y+1)^2 = 1 represent the real solutions to the equation. The set theoretic formula for this would be the set of all complex numbers with 0 imaginary part, lying on the circle (x+1)^2 + (y+1)^2 = 1.
  • #1
jaejoon89
195
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I tried graphing the following equation on Mathematica online:

http://www.wolframalpha.com/input/?i=(z*z*)+(1+i)z+((1-i)z*)+1=0

It gives complex solutions -2+i and i.

I don't understand why it lists these as the only complex solutions (why is that?). Yet it also gives as solutions as anything on the boundary of the circle, which I determined was

(x+1)^2 + (y+1)^2 = 1.

What would be the set theoretic formula for this? I'm trying to figure it out.
 
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  • #2




Thank you for sharing your findings and questions regarding the graphing of the given equation on Mathematica online. I can provide some insights and explanations to help you better understand the results you obtained.

Firstly, it is important to note that the given equation is a complex polynomial, meaning it contains complex numbers and variables. When graphing a complex polynomial, the solutions are typically represented as points in the complex plane, with the real part on the x-axis and the imaginary part on the y-axis.

In this case, the complex solutions -2+i and i are the points where the graph intersects the x-axis, indicating that these are the values of z that make the equation equal to 0. This is why Mathematica lists them as the only complex solutions.

However, as you have observed, there are also points on the boundary of the circle (x+1)^2 + (y+1)^2 = 1 that satisfy the equation. This is because these points represent the real solutions to the equation, which can also be obtained by setting the imaginary part of z to 0. In other words, these points lie on the circle in the complex plane where the imaginary part of z is equal to 0.

To answer your question about the set theoretic formula for this, it would be the set of all points on the circle (x+1)^2 + (y+1)^2 = 1 where the imaginary part of z is equal to 0. In other words, it would be the set of all complex numbers of the form x+0i, where x lies on the circle (x+1)^2 + (y+1)^2 = 1.

I hope this helps clarify the results you obtained and provides a better understanding of complex solutions and their representation on the complex plane. Keep up the good work in exploring and understanding mathematical concepts!
 

FAQ: Why Are -2+i and i the Only Complex Solutions?

What are complex functions and why do we need to graph them?

Complex functions are mathematical functions that involve complex numbers. They are used to model and describe real-world phenomena that cannot be easily represented by simple functions. Graphing complex functions allows us to visualize and understand these phenomena better.

How do we graph complex functions?

To graph a complex function, we plot points on the complex plane, where the x-axis represents the real part and the y-axis represents the imaginary part. We can then connect these points to create a continuous curve or surface that represents the complex function.

What is the difference between a real function and a complex function?

A real function takes in a real number as its input and outputs a real number. A complex function, on the other hand, takes in a complex number as its input and outputs a complex number. This means that complex functions have both real and imaginary components, while real functions only have real components.

What are some common types of complex functions?

Some common types of complex functions include polynomial functions, trigonometric functions, exponential functions, and logarithmic functions. These functions can be further classified as either algebraic or transcendental functions.

Can complex functions be graphed in three-dimensional space?

Yes, complex functions can be graphed in three-dimensional space. In this case, the x-axis represents the real part, the y-axis represents the imaginary part, and the z-axis represents the output of the function. This allows for a more comprehensive visualization of complex functions and their behavior.

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