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turin
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This expression does not represent a standing wave, it represents a complex valued propagating plane wave. If you happen to have the conjugate plane wave to this traveling in the same direction, then you have a physical (classical) wave. If you happen to have one of these plane waves traveling in the opposite direction, then you have a standing wave. The standing wave condition is met when w is a constant wrt a change in k at a particular value of w and k, not when both w and k are constant. What would that mean? Since this is a plane wave, the w and k are constant by definition in this expression. Otherwise, the expression is arbitrary, and you might as sell have written f(k,x,w,t).Sammywu said:The e^ikx+wt can only represents a standing wave when k and w are constant.
A wave packet is not a requirement for this condition. All of the individual basis functions ei(ωt-kx) themselves "have motion." A "non-moving" particular solution to the diff. eq. (a standing wave) will only arise if certain boundary conditions exist that restrict the basis functions to pairs that cancel each other's motion. In other words, standing waves occur at the edge of the Brillioun (sp?) zone where ω(k) = constant => ∂ω/∂k = 0 (zero group velocity).Sammywu said:... it's also shown that in this case, the solution actually moves with time.
Not because it moves through space, but because it is a pulse. The complex valued plane waves move through space. Two conjugates traveling together give a physical (classical) plane wave, not a wave packet, that travels through space. In order for the wave to exist in only a finite region of space, the destructive interference of the plane waves must eliminate the displacement outside of this region.Sammywu said:By this, what I see is a light pulse has to be represented by a wave packet, because it moves thru space.
Can you clarify?Sammywu said:A radiation might be able to be represented as standing waves because it bounces around us.
I don't think I agree with this justification. From what I understand, the Schroedinger equation predicts a spreading of a wavefunction for any particle whose state evolves with time.Sammywu said:I already knew that wave packet failed to represent a particle. Roughly I knew that was because it was proved that wave packet will spead out thru space and particles don't.