Why Are My Elevator Tension Calculations Incorrect?

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In summary, the elevator has two masses, m1 = 2.00 kg and m2 = 4.00 kg, connected by two cables A and B. The elevator has a downward acceleration of g/2. To calculate the tensions in cables A and B, two free body diagrams were drawn, one for each mass. After setting up the equations for the sum of forces in the y-direction, the tensions were calculated to be Fa = 19.6 N and Fb = 29.4 N. There may have been some mistakes in the previous calculations, but these are the correct answers.
  • #1
ur5pointos2sl
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My answers for this problem aren't correct. Can anyone please help me spot my mistake. Thanks.


Inside the elevator, masses m1 = 2.00kg and m2 = 4.00 kg are conncted by a cable A. Mass m1 is connected to the roof of the elevator by a cable B. The elevator has a downward acceleration of g/2. Calculate the tensions in cables A and B.

m1 = 2.00 kg
m2 = 4.00 kg
a = 9.8/2

I set up two free body diagrams.. One for m1 and one for m2

So for m1 FBD

SUMFy= 0 = Fb - 2(9.8/2) - Fa
Fb = 9.8 N

for m2 FBD

SUMFy = 0 = Fa - mg
Fa = 4(9.8/2) = 19.6 N NOW PLUGGING BACK IN
 
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  • #2
There are no answers to check. When you post them, we will check them. Nevertheless, I can see mistakes already. You say

SUMFy = 0 = Fa - mg

Why is the sum of all the forces in the y-direction zero? Are the masses not accelerating?

Also, when you say "mg" which mass are you talking about, 1 or 2?
 
  • #3
kuruman said:
There are no answers to check. When you post them, we will check them. Nevertheless, I can see mistakes already. You say

SUMFy = 0 = Fa - mg

Why is the sum of all the forces in the y-direction zero? Are the masses not accelerating?

Also, when you say "mg" which mass are you talking about, 1 or 2?

m1 = 2.00kg m2 = 4.00 kg

ok let me try this over..

FBD of m1...so here the mg will be 2kg (9.8) or would it be 2(9.8/2)?

so SUMFy = Fb - Fa - mg = ma
= Fb - Fa -(2)(9.8)=2(-9.8/2)
Fb = -9.8 N which couldn't be possible since its in tension

FBD of m2...so here mg will be 4kg (-9.8/2)?

so SUMFy= Fa - 4(9.8)= 4(-9.8/2)
Fa = 19.6 N

again I am getting the same answers as before..
 
  • #4
ur5pointos2sl said:
so SUMFy = Fb - Fa - mg = ma
= Fb - Fa -(2)(9.8)=2(-9.8/2)
Fb = -9.8 N which couldn't be possible since its in tension

How did you get -9.8 N? I don't get that when I put in the numbers. Check your algebra.

so SUMFy= Fa - 4(9.8)= 4(-9.8/2)
Fa = 19.6 N
This looks correct. Do you think it is not?
 
  • #5
kuruman said:
How did you get -9.8 N? I don't get that when I put in the numbers. Check your algebra.


This looks correct. Do you think it is not?


The instructor said 19.6 N was not the correct answer. I am not really sure of the actual correct answer.

I checked my algebra again for Fb and ended up getting 49N. I really am not sure what to think now.
 
  • #6
The Fa = 19.6 N is correct. I agree with your instructor. Now show me exactly what you do after you write down

Fb - Fa -(2)(9.8)=2(-9.8/2)
 
  • #7
kuruman said:
The Fa = 19.6 N is correct. I agree with your instructor. Now show me exactly what you do after you write down

Fb - Fa -(2)(9.8)=2(-9.8/2)

Fb - 19.6 -(2)(9.8)=2(-9.8/2)

Fb = 19.6 + 98/5 - 49/5
= 29.4 N
 
  • #8
Looks good. I think you are done.
 

FAQ: Why Are My Elevator Tension Calculations Incorrect?

1. What is the "elevator problem" in dynamics?

The "elevator problem" in dynamics refers to the study of the forces and motion involved in an elevator moving up or down. It involves analyzing the acceleration, velocity, and position of the elevator and the forces acting on it, such as gravity and the tension in the elevator cables.

2. What factors affect the motion of an elevator?

The motion of an elevator is affected by several factors, including the weight of the elevator and its passengers, the tension in the elevator cables, the friction between the elevator and the shaft, and the force of gravity.

3. How does the acceleration of an elevator change during its motion?

The acceleration of an elevator changes during its motion because the forces acting on it change. When the elevator is stationary, the acceleration is zero. As it starts moving, the acceleration increases until it reaches a constant value, and then decreases as the elevator slows down before stopping.

4. What is the difference between the upward and downward motion of an elevator?

The upward and downward motion of an elevator is different because the forces acting on it are different. When an elevator is moving upward, the tension in the cables is greater than the force of gravity, resulting in a net upward force and upward acceleration. In contrast, when an elevator is moving downward, the force of gravity is greater than the tension in the cables, resulting in a net downward force and downward acceleration.

5. How do different elevator designs affect its motion?

Different elevator designs, such as hydraulic, cable, or counterweight systems, can affect the motion of an elevator. Each design has its own unique characteristics that can influence the acceleration, velocity, and position of the elevator. For example, hydraulic elevators use fluid pressure to move the elevator car, while cable elevators use tension in cables to lift and lower the car.

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