- #1
matematikuvol
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Assume that we can expand the Helmholtz potential about [tex]T=T_c[/tex], [tex]M=0[/tex] in a standard Taylor series form of functions of the variables,
[tex]A(T,M)=\sum^{\infty}_{j=0}L_j(T)M^j=L_0(T)+L_2(T)M^2+L_4(T)M^4+...[/tex]
Why [tex]A(T,M)[/tex] must be even function of [tex]M[/tex]?
Coefficients can be expanded about [tex]T=T_c[/tex]
[tex]L_j(T)=\sum^{\infty}_{k=0}l_{jk}(T-T_c)^k=l_{j0}+l_{j1}(T-T_c)+...[/tex]
How I could no that coefficients are analytic functions od [tex]T[/tex].
[tex]A(T,M)=\sum^{\infty}_{j=0}L_j(T)M^j=L_0(T)+L_2(T)M^2+L_4(T)M^4+...[/tex]
Why [tex]A(T,M)[/tex] must be even function of [tex]M[/tex]?
Coefficients can be expanded about [tex]T=T_c[/tex]
[tex]L_j(T)=\sum^{\infty}_{k=0}l_{jk}(T-T_c)^k=l_{j0}+l_{j1}(T-T_c)+...[/tex]
How I could no that coefficients are analytic functions od [tex]T[/tex].