- #1
hitemup
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Homework Statement
A stone is thrown vertically upward with a speed of 24.0 m/s.
a) How fast is it moving when it reaches a height of 13.0 m/s?
b) How much time is required to reach this height?
c) Why are there two answers to (b)?
Homework Equations
[/B]
x = v0t +- 1/2 at2
The Attempt at a Solution
I had no problem with the first two, but I've thought I need an explanation for the third one. Here is the graph and solutions. Does the second root appear because of the stone's falling right after reaching its maximum height?
http://www4c.wolframalpha.com/Calculate/MSP/MSP42811iec8be4feb3fd0e00001afd1ed1gd449fc6?MSPStoreType=image/gif&s=16&w=86.&h=18. http://www4c.wolframalpha.com/Calculate/MSP/MSP42841iec8be4feb3fd0e00003d457bh4d7i14gi8?MSPStoreType=image/gif&s=16&w=78.&h=18.
http://www4c.wolframalpha.com/Calculate/MSP/MSP42881iec8be4feb3fd0e0000509big5995b3732e?MSPStoreType=image/gif&s=16&w=392.&h=192.&cdf=Coordinates&cdf=Tooltips
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