Why Are There Two Different Expressions for Uncertainty in Quantum Mechanics?

AI Thread Summary
The discussion centers on the two expressions for the uncertainty principle in quantum mechanics: Del(X) x Del(P) ≥ h/2π and Del(X) x Del(P) ≥ h/4π. The first expression is traditionally associated with Heisenberg's principle, while the second is derived from Fourier analysis and is favored in modern textbooks. The lecturer indicated that both can be used, but the second expression is more relevant for competitive exams. In one-dimensional scenarios, the lower bound of the uncertainty product aligns with the second expression. Understanding these distinctions is crucial for exam preparation in quantum mechanics.
Amith2006
416
2

Homework Statement


According to Heisenberg Uncertainty principle,
Del(X)xdel(P) >= h/2(pi)
But there is also another expression given in my book which is,
Del(X)xdel(P) >= h/4(pi)
I asked my lecturer why is it so? She said that, the second expression is obtained from Fourier analysis. But she also said that in calculations, you can use the first one. Which should I use in competitive exams?



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
The second one is the form given in all modern textbooks and the one you will be expected to use in your exams.
 
In 1D I believe the lower bound on the product of these uncertainties is your second expression.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up will act downwards and maximum static friction will act downwards Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top