Why can't I treat the disk as a point mass?

  • Thread starter Thread starter cory21
  • Start date Start date
  • Tags Tags
    Disk Mass Point
AI Thread Summary
The discussion revolves around the difficulty of treating a disk as a point mass when it is attached to a rod, leading to confusion in calculations. Initial attempts to solve the problem without considering the disk's rotation yielded incorrect results, while incorporating rotation provided the correct answer. Participants clarify that the disk is assumed to rotate around its center of mass while also experiencing translational motion due to its attachment to the rod. An analogy is drawn to the Moon's rotation relative to Earth to illustrate the relationship between the angles of rotation and translation. The conclusion highlights that the rigid attachment of the disk to the rod increases energy loss upon impact.
cory21
Messages
1
Reaction score
0
Homework Statement
A grandfatherโ€™s clock consists of a disk of mass, ๐‘ด attached to the end of rod of negligible mass and length, ๐‘ณ. The grandfatherโ€™s clock is hanging vertically initially from a hinge at point ๐‘จ.
A lump of clay mass, ๐’Ž moving horizontally at speed, ๐’— collides with and sticks to the center of the disk, causing the grandfatherโ€™s clock to rise to a maximum angle ๐œฝ๐’Ž๐’‚๐’™.

Which of the following is an expression for the angular speed angular speed, ๐Ž of the grandfather's clock (with a lump of clay sticking to center of disk) just after the collision? [Note: Assume that the clay is a point mass. Moment of inertia of disk about axis through center of disk I_disk=1/2MR^2]
Relevant Equations
๐ฟ๐‘ก๐‘œ๐‘ก,๐‘ƒ = ๐ฟ๐‘Ÿ๐‘œ๐‘ก๐ถ๐‘€,๐‘Ÿ๐‘œ๐‘‘ + ๐ฟ๐‘Ÿ๐‘œ๐‘ก๐ถ๐‘€,๐‘‘๐‘–๐‘ ๐‘˜ + ๐ฟ๐‘ก๐‘Ÿ๐‘Ž๐‘›๐‘ ,๐‘ƒ,๐‘Ÿ๐‘œ๐‘‘ + ๐ฟ๐‘ก๐‘Ÿ๐‘Ž๐‘›๐‘ ,๐‘ƒ,๐‘‘๐‘–๐‘ ๐‘˜
Screen Shot 2022-11-24 at 15.20.55.png


Since the question made no indication of the disk rotating about its center, I just straight up assumed that the disk did not rotate about its center, and instead treated it as a point mass. However, to my surprise my calculations did not bear me any fruit. Below is my first attempt at the solution, where you could clearly see that my calculations did not yield me an answer that's even remotely close as to what was offered in the MCQ.

Screen Shot 2022-11-24 at 15.26.42.png


If I treated the disk to have rotated around its center however, I would get D as an answer. Below is my second attempt at the solution

Screen Shot 2022-11-24 at 15.32.26.png


So, am I to assume that the disk experienced some translational motion along with rotational motion about the disk's center of mass, because the question along with the diagram isn't very clear.
 
Physics news on Phys.org
cory21 said:
So, am I to assume that the disk experienced some translational motion along with rotational motion about the disk's center of mass, because the question along with the diagram isn't very clear.
Yes. I think you are supposed to assume that the disk is attached to the rod so that the disk doesn't rotate relative to the rod.

Suppose you paint an orange line on the disk.

1669323120416.png

You can see how the disk rotates through some angle ##\phi## as the rod swings through an angle ##\theta##. What is the relation between ##\theta## and ##\phi##?
 
  • Like
Likes mfb, MatinSAR, PeroK and 2 others
Here is a figure that I posted in another thread where the same issue arose. The Moon showing the same side to the Earth is an illustration of this idea of one spin revolution per orbit revolution.

PendulumDisk.png
 
  • Like
Likes cory21 and Lnewqban
What surprised me about this scenario is that having the bob attached rigidly to the shaft, rather than on a free axle, increases the energy loss in the impact.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of ฮธ(kindly see both the pics in the pdf file). The value of ฮธ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 ยฐC. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top