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Differentiate the function: f(u) = e1/u
So, I used the chain rule and figured out that
f '(u) = (-u-2) e1/u
My question is, why do you have to use the chain rule?
I know that if f(x) = ex
then f '(x) = ex
Why can't I pretend that 1/u is x and then say that
f '(x) = ex = e1/u
In other words, does the exponent always have to be "x" only, for f '(x) = ex to work?
So, I used the chain rule and figured out that
f '(u) = (-u-2) e1/u
My question is, why do you have to use the chain rule?
I know that if f(x) = ex
then f '(x) = ex
Why can't I pretend that 1/u is x and then say that
f '(x) = ex = e1/u
In other words, does the exponent always have to be "x" only, for f '(x) = ex to work?