Why Did the Author Ignore Certain Terms in the Bent Pipe Pressure Equation?

In summary: You have the right idea. What I'm saying is that...When the jet changes direction, the pressure will increase due to the drag on the fluid.
  • #1
foo9008
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4

Homework Statement



We have the original equation P1A1 –P2A2(cos theta) +Fx = ρ Q( V2 –V1) ,

Why in the solution there , the author ignore P1A1 and P2A2cos(theta) ?

Homework Equations

The Attempt at a Solution


is the book wrong ? but the P1 and P2 are not given also...
 

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  • #2
foo9008 said:

Homework Statement



We have the original equation P1A1 –P2A2(cos theta) +Fx = ρ Q( V2 –V1) ,

Why in the solution there , the author ignore P1A1 and P2A2cos(theta) ?

Homework Equations

The Attempt at a Solution


is the book wrong ? but the P1 and P2 are not given also...
The jet is assumed to be a free jet (unconfined by a tube) so the (gauge) pressures at the very inlet and the very outlet are assumed to be zero.
 
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  • #3
Chestermiller said:
The jet is assumed to be a free jet (unconfined by a tube) so the (gauge) pressures at the very inlet and the very outlet are assumed to be zero.
Unconfined tube? What is that? i could see the pipe there
 
  • #4
foo9008 said:
Unconfined tube? What is that? i could see the pipe there
I don't think they meant to show it as a pipe. I think they meant to show it as an unconfined jet. This is my interpretation anyway.
 
  • #5
Chestermiller said:
I don't think they meant to show it as a pipe. I think they meant to show it as an unconfined jet. This is my interpretation anyway.
unconfined jet ? what is that ? what's the difference between unconfined jet and pipe?
?
 
  • #6
foo9008 said:
unconfined jet ? what is that ? what's the difference between unconfined jet and pipe?
?
When you shoot water out of a hose, that's an unconfined jet.
 
  • #7
Chestermiller said:
When you shoot water out of a hose, that's an unconfined jet.
why in unconfined tube (jet) the pressure at both end are assumed to be 0 ?
 
  • #8
With a jet from a garden hose, the air pressure at the free surface of the jet is constant at 1 atmosphere (gauge). This pressure is present throughout the jet cross section. So the pressure throughout any straight section of a jet (more then a few diameters away from the hose exit) is 0 gauge. In your problem, there is a straight section of jet coming toward the blade, and straight sections at A and B leaving the blade. The gauge pressure at these locations is 0. However, in the region where the jet is changing direction in contact with the blade (non-straight section), the fluid pressure varies rapidly from a high value at the blade surface to 0 at the free surface. This pressure variation is what enables the jet to change direction. However, the details of this flow and pressure variation in the region of curved flow are circumvented when you do the overall momentum balance. This enables you to determine the net force of the blade on the jet without ever knowing the details of the flow in the curved region.

Chet
 
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  • #9
Chestermiller said:
With a jet from a garden hose, the air pressure at the free surface of the jet is constant at 1 atmosphere (gauge). This pressure is present throughout the jet cross section. So the pressure throughout any straight section of a jet (more then a few diameters away from the hose exit) is 0 gauge. In your problem, there is a straight section of jet coming toward the blade, and straight sections at A and B leaving the blade. The gauge pressure at these locations is 0. However, in the region where the jet is changing direction in contact with the blade (non-straight section), the fluid pressure varies rapidly from a high value at the blade surface to 0 at the free surface. This pressure variation is what enables the jet to change direction. However, the details of this flow and pressure variation in the region of curved flow are circumvented when you do the overall momentum balance. This enables you to determine the net force of the blade on the jet without ever knowing the details of the flow in the curved region.

Chet
form your explanation above , do you mean the jet coming from a hose which enter the stationary blade?
why the fluid pressure will become 0 to enable the jet to change direction ? IMO, when the jet change direction , it will slow down , pressure will increase , right ? why you said it become 0 ?
 
  • #10
foo9008 said:
form your explanation above , do you mean the jet coming from a hose which enter the stationary blade?
why the fluid pressure will become 0 to enable the jet to change direction ? IMO, when the jet change direction , it will slow down , pressure will increase , right ? why you said it become 0 ?
You have the right idea. What I'm saying is that it will increase at the blade surface, but, at the free surface, the jet is still in contact with the air, so the pressure at the free surface will still be zero. In the region where the jet is in contact with the blade (and changing direction), the fluid pressure will vary across the diameter of the jet, from a high value at the blade surface to zero at its free surface.
 
  • #11
Chestermiller said:
You have the right idea. What I'm saying is that it will increase at the blade surface, but, at the free surface, the jet is still in contact with the air, so the pressure at the free surface will still be zero. In the region where the jet is in contact with the blade (and changing direction), the fluid pressure will vary across the diameter of the jet, from a high value at the blade surface to zero at its free surface.
do you mean both my idea aforementioned correct ?
Chet form your explanation above , do you mean the jet coming from a hose which enter the stationary blade?
why the fluid pressure will become 0 to enable the jet to change direction ? IMO, when the jet change direction , it will slow down , pressure will increase , right ? why you said it become 0 ?


do you mean water pressure ?
 
  • #12
foo9008 said:
do you mean both my idea aforementioned correct ?
Chet form your explanation above , do you mean the jet coming from a hose which enter the stationary blade?

Yes, if you want to think of it that way.
why the fluid pressure will become 0 to enable the jet to change direction ? IMO, when the jet change direction , it will slow down , pressure will increase , right ? why you said it become 0 ?

do you mean water pressure ?
I don't know how to say it any better. In the region where the liquid is changing direction when in contact with the blade, the pressure within the liquid varies across the cross section of the jet from a high value at the blade surface (as you said, pressure will increase ") to a value of zero at the free surface of the jet, all within the same cross section of the jet.
 
  • #13
Chestermiller said:
Yes, if you want to think of it that way.

I don't know how to say it any better. In the region where the liquid is changing direction when in contact with the blade, the pressure within the liquid varies across the cross section of the jet from a high value at the blade surface (as you said, pressure will increase ") to a value of zero at the free surface of the jet, all within the same cross section of the jet.
do yuou mean the water pressure increases from the inlet to the bent part of the pipe , then it decreases to 0 at the outlet of the pipe ? since at the outlet of the pipe , the pressure acting is no longer water pressure , but atmospheric pressure?
 
  • #14
foo9008 said:
do yuou mean the water pressure increases from the inlet to the bent part of the pipe , then it decreases to 0 at the outlet of the pipe ?
No, no, no. I said it increases across the diameter of the jet. A pressure gradient across the diameter of the jet is required to change the direction of all parcels of fluid comprising the jet (both near the wall and near the free surface), because each parcel is being accelerated (i.e.,changing direction).
since at the outlet of the pipe , the pressure acting is no longer water pressure , but atmospheric pressure?
You need to understand 2 things:
1. Pressure is continuous at a free surface, and the pressure of the water must match the pressure of the air at a free surface.
2. Pressure does not only vary along streamlines. It can also vary in the direction perpendicular to streamlines.
 
  • #15
Chestermiller said:
No, no, no. I said it increases across the diameter of the jet. A pressure gradient across the diameter of the jet is required to change the direction of all parcels of fluid comprising the jet (both near the wall and near the free surface), because each parcel is being accelerated (i.e.,changing direction).

You need to understand 2 things:
1. Pressure is continuous at a free surface, and the pressure of the water must match the pressure of the air at a free surface.
2. Pressure does not only vary along streamlines. It can also vary in the direction perpendicular to streamlines.
I thought when the water is flowing and friction is ignored , the velocity of water across the straight pipe would be constant ? thus , the pressure gradient would be constant ? ( consequence of beroulli's principle ) ?
 
  • #16
foo9008 said:
I thought when the water is flowing and friction is ignored , the velocity of water across the straight pipe would be constant ? thus , the pressure gradient would be constant ? ( consequence of beroulli's principle ) ?
That's only if the streamlines are straight. If the streamlines are curved, the pressure varies between streamlines. How else could the parcels of fluid be accelerated normal to a curved path (centripetal acceleration)? After the streamlines straighten out again, the pressure becomes uniform across the cross section again.
 
  • #17
Chestermiller said:
You have the right idea. What I'm saying is that it will increase at the blade surface, but, at the free surface, the jet is still in contact with the air, so the pressure at the free surface will still be zero. In the region where the jet is in contact with the blade (and changing direction), the fluid pressure will vary across the diameter of the jet, from a high value at the blade surface to zero at its free surface.

at the free surface , the pressure acting is the atmospheric pressure , right ? why you said it's 0 ? is it because of gauge pressure? why can't we use absolute pressure in the calculation?
 
  • #18
foo9008 said:
at the free surface , the pressure acting is the atmospheric pressure , right ? why you said it's 0 ? is it because of gauge pressure?
Yes.
why can't we use absolute pressure in the calculation?
We can, but it's easier to use gauge pressure.
 

FAQ: Why Did the Author Ignore Certain Terms in the Bent Pipe Pressure Equation?

1. What is pressure in bent pipe?

Pressure in bent pipe refers to the force per unit area that is exerted on the walls of a pipe as a result of fluid flowing through it. This pressure is caused by the resistance of the fluid to flow and can vary depending on the fluid's velocity, density, and the geometry of the pipe.

2. How does pressure change in a bent pipe?

In a bent pipe, pressure changes due to the change in direction of the fluid flow. As the fluid moves through the curve, it experiences a centrifugal force that causes it to push against the inner walls of the pipe, resulting in an increase in pressure on the outer side of the curve and a decrease on the inner side.

3. What factors affect pressure in a bent pipe?

The main factors that affect pressure in a bent pipe are the fluid's velocity, density, and the curvature of the pipe. Higher fluid velocities and densities, as well as tighter curves, will result in higher pressure in the bent pipe.

4. How is pressure measured in a bent pipe?

Pressure in a bent pipe can be measured using a pressure gauge or manometer. These instruments use the principle of fluid pressure to determine the force per unit area exerted by the fluid on the pipe's walls. The units of measurement for pressure are typically pounds per square inch (psi) or pascals (Pa).

5. What are the applications of understanding pressure in bent pipe?

Understanding pressure in bent pipe is important in various industries, such as plumbing, hydraulics, and fluid dynamics. It is also crucial in designing and maintaining pipelines, as well as in optimizing the flow of fluids through curved pipes. Additionally, knowledge of pressure in bent pipe is essential in preventing and troubleshooting issues such as leaks and blockages in pipelines.

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