Why Do Cosine and Sine Give Different Angles for the Same Vector?

The correct angle is 315 degrees.In summary, the problem is to find the magnitude and smallest positive angle from the positive x-axis to the vector OP corresponding to a given vector a. Using the equations a1 = ||a|| * cos theta and a2 = ||a|| * sin theta, the magnitude of a is found to be 3√2. However, since the vector is in the fourth quadrant, the correct angle is 315 degrees, not 45 degrees or -45 degrees.
  • #1
k_squared
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Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = [tex]\sqrt{}[/tex](9+9) = 3[tex]\sqrt{}[/tex]2
a1 = 3[tex]\sqrt{}[/tex]2 * cos theta

=1/[tex]\sqrt{}[/tex]2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/[tex]\sqrt{}[/tex]2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
 
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  • #2
k_squared said:

Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = [tex]\sqrt{}[/tex](9+9) = 3[tex]\sqrt{}[/tex]2
a1 = 3[tex]\sqrt{}[/tex]2 * cos theta

=1/[tex]\sqrt{}[/tex]2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/[tex]\sqrt{}[/tex]2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
arccos produces an angle between 0 and 180 degrees, while arcsin produces an angle between -90 and + 90 degrees. Since your vector is in the fourth quadrant, an angle of 45 degrees wouldn't be right, nor would -45 degrees, since the problem asks for a positive angle.
 

FAQ: Why Do Cosine and Sine Give Different Angles for the Same Vector?

What are the basic trigonometric functions?

The basic trigonometric functions are sine, cosine, and tangent. These functions are used to determine the relationship between the sides and angles of a right triangle.

How do you find the angle of a vector using trigonometry?

To find the angle of a vector using trigonometry, you can use the inverse trigonometric functions. For example, if you know the lengths of the sides of a right triangle, you can use the inverse tangent function to find the angle.

What is the difference between a vector and a scalar?

A vector is a quantity that has both magnitude and direction, while a scalar only has magnitude. In trigonometry, vectors are typically represented as arrows with a specific length and direction, while scalars are represented as numbers.

How do you calculate the magnitude of a vector?

The magnitude of a vector can be calculated using the Pythagorean theorem. This involves finding the square root of the sum of the squares of the vector's components. Alternatively, you can use the trigonometric functions to calculate the magnitude if you know the angle and length of the vector.

How is trigonometry used in real life?

Trigonometry has many real-life applications, such as in navigation, engineering, and architecture. It is also used in fields such as physics, astronomy, and geography to calculate distances, angles, and trajectories. Additionally, trigonometry is used in video game design, computer graphics, and animation to create realistic movements and perspectives.

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