- #1
Bensky
- 82
- 0
Another question on electric fields. :(
I have another problem I don't understand on electric fields. I thought I understood these after my last post, but I guess not. I'm guessing it has something to do with the signs of the forces, but I am not sure.
Particles of charge Q1 = +68 µC, Q2 = +49 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two.
Figure 16-37
F = KQ_1Q_2/r^2
F = K * Q1Q2/r^2
F_12 = (K)(6.8 X 10-5)(4.9 X 10-5)/.35^2
F_12 = 244.8 N (goes to the left, repels)
F_13 = K(Q1Q2)/r^2
F_13 = (K)(6.8 X 10-5)(4.9 X 10-5)/.7^2
F_13 ~= 100 N (goes to the right, attracts)
F_q1 = -244.8 + 100
F_q1 = -144.8 N (wrong)
However, the second part of the question asked which direction it went in, and based on my answer, I put "left" and that was correct. I'm confused.
I have another problem I don't understand on electric fields. I thought I understood these after my last post, but I guess not. I'm guessing it has something to do with the signs of the forces, but I am not sure.
Homework Statement
Particles of charge Q1 = +68 µC, Q2 = +49 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two.
Figure 16-37
Homework Equations
F = KQ_1Q_2/r^2
The Attempt at a Solution
F = K * Q1Q2/r^2
F_12 = (K)(6.8 X 10-5)(4.9 X 10-5)/.35^2
F_12 = 244.8 N (goes to the left, repels)
F_13 = K(Q1Q2)/r^2
F_13 = (K)(6.8 X 10-5)(4.9 X 10-5)/.7^2
F_13 ~= 100 N (goes to the right, attracts)
F_q1 = -244.8 + 100
F_q1 = -144.8 N (wrong)
However, the second part of the question asked which direction it went in, and based on my answer, I put "left" and that was correct. I'm confused.