Why Does a Toy Airplane on a String Tilt When It Flies in Circles?

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In summary: You almost have it! In summary, when a toy airplane with a mass m is hung on a string from the ceiling and its motor is started, it moves around in a circle with constant speed, making an angle θ with the vertical. By balancing the vertical forces on the plane, the tension T in the string can be found to be T=mg/cos(θ). Using the equation for circular motion, T can also be expressed as T=m(v^2/r)/sin(θ), and by setting these two expressions equal to each other, the speed v can be found to be sqrt[(l*(sinθ)^2)/r]. Therefore, the period of rotation T, can be written as T=2πr
  • #1
kirafreedom
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Homework Statement



A particular type of toy airplane available in stores have little motors attached to them. Consider hanging one on a string from the ceiling and starting its motor. As it moves around in a circle with constant speed the stringwill make an angle with the vertical as shown in the diagram.
a) Assuming the plane has a mass m, find T, the tension in the string, in terms of m, θ, and g, by balancing the vertical forces on the plane.
b) Now use the equation for circular motion to solve for T in terms of m, θ, and v, (the speed of the plane), and l, (the length of the string).
c) By setting these two expressions for T equal to each other, find v in terms of θ, g, and l.
d) If you were to try this, you would find v difficult to measure directly. Write the period of rotation T, (not to beconfused with the tension), in terms of θ.

Homework Equations


T*cos(θ)=mg
r=l*sin(θ)
T*sin(θ)=m(v^2/r)

The Attempt at a Solution


a) T*cos(θ)=mg
T=mg/cos(θ)

b) T*sin(θ)=m(v^2/r)
T=[m(v^2/r)]/sin(θ)
r= [T*sin(θ)v^2]/m

r=l*sin(θ)
[T*sin(pheta)v^2]=l*sin(θ)
T=[l*sin(θ)m]/v^2

c) [l*sin(θ)m]/v^2=[m(v^2/r)]/sin(θ)
v=squart[(l*(sinθ)^2)/r]

d)
I am not sure
 
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  • #2
Ok for a)
BUT: pay attention to the math in b)... I didn't understand what you did but you did something wrong. Hint: it is simpler than that... you got the expression for ##T## right, then just substitute the expression for ##r## in terms of ##l## and ##\theta##
c) Need correct b) first :wink:
d) Use the relation between period and velocity (keep in mind for you ##v## is the speed of the plane, therefore the tangential velocity) http://en.wikipedia.org/wiki/Circular_motion#Uniform_circular_motion
 
  • #3
kirafreedom said:
b) T*sin(θ)=m(v^2/r)
T=[m(v^2/r)]/sin(θ)
r= [T*sin(θ)v^2]/m
Try that last step again.
 

FAQ: Why Does a Toy Airplane on a String Tilt When It Flies in Circles?

What is a tension-toy airplane?

A tension-toy airplane is a small toy that is powered by a rubber band or spring-loaded mechanism. When the tension is released, it propels the toy airplane forward, mimicking the flight of a real airplane.

How does a tension-toy airplane work?

A tension-toy airplane works by storing energy in a rubber band or spring. When the tension is released, the energy is released and propels the airplane forward. Some tension-toy airplanes also have propellers or wings that spin, adding to the flight effect.

Are tension-toy airplanes safe for children?

Tension-toy airplanes can be safe for children, but it is important to supervise them while playing with the toy. The rubber band or spring can cause injury if not handled properly. It is also important to make sure the toy is age-appropriate and does not have small parts that can be a choking hazard.

Can tension-toy airplanes be used indoors?

Yes, tension-toy airplanes can be used indoors, but it is important to have a large enough space to fly the toy without causing damage or injury. Soft surfaces like carpet or grass can help cushion any potential crashes.

Are there any educational benefits to playing with tension-toy airplanes?

Playing with tension-toy airplanes can help develop hand-eye coordination and fine motor skills. It can also spark interest in aviation and physics, as children can observe how the toy moves and try to understand the principles behind it.

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