Why Does Adding Strong Acid Change the Color of Metal Ion Solutions?

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In summary, the color of a solution fades when a cation is mixed with a strong acid. This is due to the formation of colorless complexes, and the dilution of the cation.
  • #1
Eureka99
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Hi everybody!
Does anyone knows why when a cation is mixed with a strong acid the color of the solution (if it's colored) fades a little bit, depending on the concentration of the acid?
For example an "orangy" solution that contains Fe3+, If HCl 2 M is added the color turns yellow, and if H2SO4 6 M is added instead it turns transparent. Is it due to the formation of colorless complexes (like FeCl4-)? Is it even possible that a complex is formed adding only the acid, with an excess of the ligand (like in the first case Cl-)?
The same thing happens with, Fe 2+, Co2+, Cr 3+, Ni 2+ and Co2+ solutions ( I did it in the laboratory) , and I'm not able to explain it.
 
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  • #2
Definitely there are changes in complexes present. OH- is a ligand, when you lower pH you remove it from the solution shifting the equilibrium. Cl- is a ligand, when you add it to the solution, you shift the equilibrium.

But perhaps the simplest explanation is that you are diluting the cation adding the acid?
 
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  • #3
Ok. Even if it's due to the dilution, isn't the dilution also based on another equilibrium of a complex that is shifted? I know for example, that most of the time, increasing [H+] concentration, if the ligand comes from a weak acid, more cations are freed in the solution and colors can fade, as the concentration of the complex decreases. Can It also possibly be, something about that concept?
 
  • #4
Eureka99 said:
isn't the dilution also based on another equilibrium of a complex

No. Do you know the Beer-Lambert law? Just lowering the concentration makes the color fade.

Neither of the acids you have listed is a weak one, so that doesn't matter here (but yes, it can be an important factor in other cases).
 
  • #5
Borek said:
No. Do you know the Beer-Lambert law? Just lowering the concentration makes the color fade.

Neither of the acids you have listed is a weak one, so that doesn't matter here (but yes, it can be an important factor in other cases).

I don't know much about this law, but If I didn't get it wrong is due to optics reasons the fading color. Anyway now it's a bit clearer to me :smile:
Thank you for the help!
 

FAQ: Why Does Adding Strong Acid Change the Color of Metal Ion Solutions?

What is a solution?

A solution is a homogeneous mixture of two or more substances. It is made up of a solute, which is the substance being dissolved, and a solvent, which is the substance in which the solute is dissolved.

What are the different types of solutions?

There are three main types of solutions: solid solutions, liquid solutions, and gaseous solutions. Solid solutions are a mixture of two or more solids, such as alloys. Liquid solutions are a mixture of two or more liquids, such as saltwater. Gaseous solutions are a mixture of two or more gases, such as air.

What factors affect the solubility of a substance?

The solubility of a substance can be affected by several factors, including temperature, pressure, and the nature of the solute and solvent. Generally, an increase in temperature and pressure can increase the solubility of a substance, while the nature of the solute and solvent can also play a role in their ability to dissolve in each other.

How do you calculate the concentration of a solution?

The concentration of a solution can be calculated by dividing the amount of solute by the amount of solvent or solution. This can be expressed as a percentage, parts per million (ppm), or molarity (moles per liter).

What is the difference between a saturated and unsaturated solution?

A saturated solution is one in which the maximum amount of solute has been dissolved in the solvent at a given temperature and pressure. An unsaturated solution is one in which more solute can still be dissolved in the solvent. If more solute is added to a saturated solution, it will not dissolve and will form a precipitate.

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