- #1
L89
- 10
- 0
Hi, I have a question concerning the attached diagram:
The question which accompanied the diagram is: Why does the aluminium rod (the one that lies across the other two) slow down when a current is produced?
The official answer is: "A current is produced in the rod which experiences a force in an opposite direction to the original motion, therefore slowing down the motion."
However, I do not really understand this and tried to formulate my answer. This is my attempt:
As the rod moves towards the right , its velocity is at 90° to the magnetic field. Thus the electrons in it will have the same velocity. Hence, according to the Left Hand Slap Rule [opposite of RightHSR for positive particles], a magnetic force is exerted on them and they move to the further end of the roller. The closer end becomes positively charged. Meanwhile, this potential difference induces a voltage across the rod thus causing electrons to flow anticlockwise. The two electron motions are opposite, thus the total current is small. Hence the magnetic force exerted on the rod (as current is at 90° to field) is small, and a smaller speed is produced.
MY QUESTION IS THIS: Is my answer correct? If it's not can someone enlighten me?
Help will be appreciated
L89
The question which accompanied the diagram is: Why does the aluminium rod (the one that lies across the other two) slow down when a current is produced?
The official answer is: "A current is produced in the rod which experiences a force in an opposite direction to the original motion, therefore slowing down the motion."
However, I do not really understand this and tried to formulate my answer. This is my attempt:
As the rod moves towards the right , its velocity is at 90° to the magnetic field. Thus the electrons in it will have the same velocity. Hence, according to the Left Hand Slap Rule [opposite of RightHSR for positive particles], a magnetic force is exerted on them and they move to the further end of the roller. The closer end becomes positively charged. Meanwhile, this potential difference induces a voltage across the rod thus causing electrons to flow anticlockwise. The two electron motions are opposite, thus the total current is small. Hence the magnetic force exerted on the rod (as current is at 90° to field) is small, and a smaller speed is produced.
MY QUESTION IS THIS: Is my answer correct? If it's not can someone enlighten me?
Help will be appreciated
L89