- #1
gangsta316
- 30
- 0
Why is it [itex]E = \frac{1}{2} C V^2[/itex]? I mean why is it half? It seems to arise from integration but can't we say that Q = CV and then multiply both sides by V to give QV = CV^2? The left hand side is equal to work done because voltage is defined by work done/charge.