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tkegis
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Homework Statement
Motorcycle in a vertical loop.
Traveling at 50 m/s.
Assume g=10 m/s^2
Find the maximum height of the loop. h=?
Homework Equations
F(net) = F(cent) + F(grav)
F(cent) = mv^2/r
F(grav) = mg
(change) KE = (change) PE
KE = 1/2 mv^2
PE = mgh
The Attempt at a Solution
F(net) solution gives me 500m
F(cent) = F(grav)
mv^2/r = mg
v^2 = gr
v^2/g = r
r = 250m
the height is 500m
Conservation of Energy solution gives me 125m
KE = PE
1/2mv^2 = mgh
(v^2)/(2g) = h
125m = hI found this in an MCAT practice book and they said the correct answer was 500m.
Why does the conservation of energy formula not work here?
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