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Ask1122
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Hi all, everyone know that molecules hold more energy in their gasous phase than their liquid phrase, i would like to ask why is that so?
If i look at bernoulli's equation and the ideal gas equation, let's say both phases are filled in their own containers which has the same volume and pressure, from ideal gas equation P*V=mRT, PV will give me the energy, whereas in bernoulli's equation, if i rearrange the equation to => P + v^2*rho/2 +rho*g*h = Total pressure, then if i times the volume of the cylinder, i would get energy within the system, then if you look at the equation, wouldn't liquid phase has more energy than the gasous phase?
Thanks!
If i look at bernoulli's equation and the ideal gas equation, let's say both phases are filled in their own containers which has the same volume and pressure, from ideal gas equation P*V=mRT, PV will give me the energy, whereas in bernoulli's equation, if i rearrange the equation to => P + v^2*rho/2 +rho*g*h = Total pressure, then if i times the volume of the cylinder, i would get energy within the system, then if you look at the equation, wouldn't liquid phase has more energy than the gasous phase?
Thanks!