Why does gravity dictate min.velocity for centripetal force?

In summary: So the string must be slack at the top of the circle, and the yo-yo falls.In summary, the minimum speed needed to swing a yo-yo in a vertical circle while keeping the string fully extended is when the centrifugal force is equal to the force of gravity. If the speed is too slow, the string will become slack at the top of the circle and the yo-yo will fall. This is because the string is unable to exert the necessary upward force on the yo-yo.
  • #1
aeromat
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0

Homework Statement


You are playing with a yo-yo with a mass of 225 g. The full length
of the string is 1.2 m. You decide to see how slowly you can swing
it in a vertical circle while keeping the string fully extended, even
when the yo-yo is at the top of its swing.
(a) Calculate the minimum speed at which you can swing the yo-yo
while keeping it on a circular path.

Homework Equations


Fg = mg
Fc = v^2/r

The Attempt at a Solution


All I want to know is why is it that the "centripetal force has to be exactly equal to the force of gravity" when the object will be at its smallest possible velocity (aka minimum velocity)?

Why is it that gravity is supplying the centripetal force needed for the object to maintain in circular motion at the least possible velocity?
 
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  • #2
Gravity is not supplying the centripetal force (perhaps that term is causing your problem). The centrifugal force must at least equal gravity or your yo-yo will not make it over the top.
 
  • #3
Another way to look at it:

Solve for the force the string needs to exert on the yo-yo to make it swing in in a vertical circle. Then realize that at the top of the circle, if the speed is too small, then the string needs to push up on the yo-yo. But unless you have a stiff string, it can't push.
 

FAQ: Why does gravity dictate min.velocity for centripetal force?

Why does gravity play a role in determining the minimum velocity for centripetal force?

Gravity is a fundamental force that exists between any two objects with mass. When an object is moving in a circular path, it experiences a centripetal force that is directed towards the center of the circle. This force is provided by the gravitational attraction between the object and the center of the circle.

How does the strength of gravity affect the minimum velocity for centripetal force?

The strength of gravity is directly proportional to the mass of the objects and inversely proportional to the square of the distance between them. This means that as the mass of the objects increases or the distance between them decreases, the gravitational force also increases. Therefore, a stronger gravitational force will require a higher minimum velocity for an object to maintain a circular path.

Is the minimum velocity for centripetal force affected by the mass of the object?

Yes, the mass of the object does affect the minimum velocity for centripetal force. This is because the greater the mass of the object, the greater the centripetal force needed to keep it in a circular path. Therefore, a larger mass will require a higher minimum velocity to maintain that path.

How does the radius of the circular path affect the minimum velocity for centripetal force?

The minimum velocity for centripetal force is inversely proportional to the radius of the circular path. This means that as the radius increases, the minimum velocity decreases. This is because a larger radius results in a longer distance to travel in the same amount of time, requiring a slower minimum velocity to maintain the circular path.

Can an object have a minimum velocity for centripetal force if there is no gravity present?

No, an object cannot have a minimum velocity for centripetal force if there is no gravity present. This is because without gravity, there is no centripetal force acting on the object. In the absence of gravity, an object will continue to move in a straight line at a constant velocity, rather than in a circular path.

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