- #1
Punkyc7
- 420
- 0
A 1.2 kg horizontaal uniform tray is attached to a vertical ideal spring of force constant 195N/m and a 275 g metal ball is in the tray. The spring is below the tray, so it can oscillate up and down. The tray is then pushed down 13 cm below its equilibrium point called point A and released from rest.
how long does it take the ball to leave the tray from point A?
So the time it took should equal T/4+ the time it takes to get to the spot it leaves at
T=.5464
x=Acos([itex]\omega[/itex]t)
x is .07420
A is .13
[itex]\omega[/itex]=sqrt(k/m)=11.4979
solving for t at dsiplacement 0 I get t=.0837
so my total time is .22. Some reason that is not the right answer and i can't figure out where i went wrong
how long does it take the ball to leave the tray from point A?
So the time it took should equal T/4+ the time it takes to get to the spot it leaves at
T=.5464
x=Acos([itex]\omega[/itex]t)
x is .07420
A is .13
[itex]\omega[/itex]=sqrt(k/m)=11.4979
solving for t at dsiplacement 0 I get t=.0837
so my total time is .22. Some reason that is not the right answer and i can't figure out where i went wrong