Why Does the Derivative of 2 + tan(x/2) Include a .5 Term?

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The derivative of the function 2 + tan(x/2) is .5 + sec^2(x/2) due to the application of the chain rule. The constant term 2 contributes a derivative of 0, while the derivative of tan(x/2) requires the chain rule, resulting in the .5 factor. The derivative of x/2 is 1/2, which is why this term appears in the final result. Understanding the chain rule is crucial for correctly calculating derivatives of composite functions. The discussion highlights the importance of recognizing how derivatives of inner functions affect the overall derivative.
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I understand everything except why the derivative of 2 + tan (x/2) is .5 + sec^2(x/2)
I don't understand the .5 part. I understand the sec part. I would think the derivative of 2 would be C, or just disappear.
 
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never mind. I got it. I've got to use the chain rule. the derivative of t/2 is 1/2
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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