- #1
arunma
- 927
- 4
I have a question about the hydrostatic equation for a star's central pressure. I know that the central pressure for a star is,
[tex]\dfrac{dP}{dr} = \rho \dfrac{G M}{r^2}[/tex]
My question is: why does this blow up at [tex]r = 0[/tex]? Because of the singularity, I'm not sure how I can integrate the equation in order to obtain the total gravitational pressure on a star. Can anyone help? Thanks.
[tex]\dfrac{dP}{dr} = \rho \dfrac{G M}{r^2}[/tex]
My question is: why does this blow up at [tex]r = 0[/tex]? Because of the singularity, I'm not sure how I can integrate the equation in order to obtain the total gravitational pressure on a star. Can anyone help? Thanks.