Why Does the Factor of 1/2 Appear in Dynamic Pressure Calculations?

In summary, the conversation discusses the use of the Simplify step in the calculation of the derivative and the concept of anti-derivative and integration. The question of whether it is acceptable to multiply both sides of an equation by 'dx' and integrate is also raised. It is noted that this method does not account for the constant of integration, which is required to specify an initial condition.
  • #1
malindenmoyer
31
0
Please refer to this website: http://www.grc.nasa.gov/WWW/K-12/airplane/dynpress.html"

In the "Simplify" step, where does the factor of 1/2 come from? I must be missing something simple...

Thanks for the help!
 
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  • #2
What is the derivative of d(u^2)/dx? How does that differ from the second term in the 'algebra step'?
This relates to the concept of anti-derivative and integration. Have you studied that yet?
 
  • #3
I get it now--I'm not used to a 'physicist's' calculus. Would it be proper to simply multiply each side of the original equation by 'dx' and integrate each side with the respective variables? This leaves (r*u^2)/2=-p -> (r*u^2)/2+p=0

Is there a reason why this method is not preferable?
 
  • #4
Maybe to re-inforce that a constant of integration is required to specify an initial condition? The method you used does not account for the 'constant' as you have the static + dynamic pressure equal to zero instead of the 'total pressure".

Remember, indefinite integrals require a constant of integration.
 
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  • #5


I am happy to provide a response to your question about the derivation of dynamic pressure. The factor of 1/2 in the "Simplify" step comes from the application of Bernoulli's equation, which relates the pressure and velocity of a fluid in motion. In this case, we are looking at the dynamic pressure, which is the difference between the total pressure and the static pressure. When we apply Bernoulli's equation to this situation, we can see that the factor of 1/2 arises as a result of simplifying the equation. This factor is necessary to correctly relate the dynamic pressure to the velocity of the fluid. I hope this helps to clarify the derivation for you. If you have any further questions, please do not hesitate to ask.
 

FAQ: Why Does the Factor of 1/2 Appear in Dynamic Pressure Calculations?

What is dynamic pressure derivation?

Dynamic pressure derivation is a mathematical process used to calculate the dynamic pressure of a fluid in motion. It is an important concept in fluid mechanics and is often used in engineering and science applications.

How is dynamic pressure derived?

Dynamic pressure is derived using the Bernoulli's principle, which states that the total energy of a fluid in motion remains constant. The derivation involves calculating the change in kinetic energy of the fluid as it moves through a fluid flow field.

What is the significance of dynamic pressure in fluid mechanics?

Dynamic pressure is an important parameter in fluid mechanics as it helps determine the force exerted by a fluid in motion on a surface. It is also used to calculate other fluid properties such as velocity and flow rate.

What are the units of dynamic pressure?

The units of dynamic pressure are typically in Newtons per square meter (N/m^2) or Pascals (Pa). However, it can also be expressed in other units such as pounds per square inch (psi) or atmospheres (atm).

How is dynamic pressure used in real-world applications?

Dynamic pressure is used in a variety of real-world applications such as aerodynamics, hydrodynamics, and meteorology. It is used to design and analyze aircraft, rockets, and other vehicles that move through fluids. It is also used in weather forecasting to predict the behavior of air masses and storms.

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