- #1
marchingt9
- 1
- 0
Missing homework template due to originally being posted in other forum
x' =-5x-y
y' =4x-y
I got
x=ae^-3t+bte^-3t
y=-2bte^-3t+2ae^-3t+be^-3t
a=0 b=0
The answer is
x=e^(-3t+3)-te^(-3+3)
y=-e^(-3+t)+2te^(-3+3)
I don't understand where the +3 comes from
y' =4x-y
I got
x=ae^-3t+bte^-3t
y=-2bte^-3t+2ae^-3t+be^-3t
a=0 b=0
The answer is
x=e^(-3t+3)-te^(-3+3)
y=-e^(-3+t)+2te^(-3+3)
I don't understand where the +3 comes from