- #1
blizzard750
- 2
- 0
y1(t) = t^(2)+5t, y2(t) = t^(2)-5t
I know that these functions are linearly independent because they are not scalar multiples, but every time that i do the Wronskian i get 0.
[t^(2) + 5t t^(2)-5t]
[2t+5 2t -5]
(2t^(3) -25t) - (2t^3-25t) = 0 my instructor some how gets 20t please tell me how
I know that these functions are linearly independent because they are not scalar multiples, but every time that i do the Wronskian i get 0.
[t^(2) + 5t t^(2)-5t]
[2t+5 2t -5]
(2t^(3) -25t) - (2t^3-25t) = 0 my instructor some how gets 20t please tell me how