- #1
zzoo4
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Why does work equals kinetic energy of friction??
After hitting a long fly ball that goes over the right fielder’s
head and lands in the outfield, the batter decides to keep going
past second base and try for third base. The 62.0-kg player begins sliding 3.40 m from the base with a speed of 4.35 m/s. If
the player comes to rest at third base, (a) how much work was
done on the player by friction?
w=fd
ke=.5mv^2
I already know how to do this but
KE= .5X6.2x4.35^2 = -587J
But Why do we use Kinetic energy equation to find the work of friction?
Homework Statement
After hitting a long fly ball that goes over the right fielder’s
head and lands in the outfield, the batter decides to keep going
past second base and try for third base. The 62.0-kg player begins sliding 3.40 m from the base with a speed of 4.35 m/s. If
the player comes to rest at third base, (a) how much work was
done on the player by friction?
Homework Equations
w=fd
ke=.5mv^2
The Attempt at a Solution
I already know how to do this but
KE= .5X6.2x4.35^2 = -587J
But Why do we use Kinetic energy equation to find the work of friction?