Why doesn't the detector affect the result?

  • B
  • Thread starter Mervinoc
  • Start date
  • Tags
    Detector
In summary: That's what's called a "probability amplitude" and it's a very important concept in relativistic QT. Without that idea one would get weirdnesses such as EPR paradoxes in which particles exchange (teleportation) information faster than the speed of light.In summary, the detector in the double slit experiment does not affect the result because it behaves like a wave when not detected and like a particle when detected.
  • #1
Mervinoc
2
0
TL;DR Summary
Why doesn't the detector effect the result of the double split experiment?
Why doesn't the detector effect the result of the double split experiment
 
Physics news on Phys.org
  • #2
What detector? What result?
 
  • Like
Likes topsquark, Vanadium 50 and vanhees71
  • #3
Mervinoc said:
TL;DR Summary: Why doesn't the detector effect the result of the double split experiment?

Why doesn't the detector effect the result of the double split experiment
What is the "double split experiment"?
 
  • #4
StevieTNZ said:
What is the "double split experiment"?
1666948400580.png
 
  • Haha
Likes DennisN, topsquark, berkeman and 4 others
  • #5
Mervinoc said:
Why doesn't the detector effect the result of the double split experiment
You are getting these confused responses because usually when people talk about “the double slit experiment” they mean a hypothetical setup involving a barrier with two slits in it and illuminated by a beam of particles. In this setup the presence or absence of a detector at the slits does affect the result, so your question (“Why doesn’t the detector affect the result?”) leaves us wondering what setup you are considering.

If you can be more specific about that setup you will get better and more helpful answers.
 
  • Like
Likes topsquark, Lord Jestocost and PeroK
  • #6
  • #7
In the double split experiment a photon of light behaves like a particle when detected and behaves as wave when not
 
  • #8
Mervinoc said:
In the double split experiment a photon of light behaves like a particle when detected and behaves as wave when not
double slit
so the detector does affect the result?
 
  • #9
Mervinoc said:
In the double split experiment a photon of light behaves like a particle when detected and behaves as wave when not
Actually it always behaves like a particle, in that it lands at a single point on the screen and makes a single dot on the photographic film at that point. The interference pattern, if any, builds up over time as more dots appear in some regions and fewer in other regions. The presence or absence of a detector changes the probability of a particle landing at various points on the screen and hence the pattern that eventually builds up.

This quantum mechanical double slit experiment is very different than the classical double slit experiement (first done by Thomas Young early in the 19th century) in which light passes through the two slits and bright and dark regions appear on the screen as a result of interference.
 
Last edited:
  • Like
Likes vanhees71, topsquark and PeroK
  • #10
I think this overemphasis of the "particle picture" is a source of misunderstanding. A photon has the least particle-like properties of any "elementary particle", because it's massless and has spin 1 and as such has no position observable in the usual sense. In relativistic QT it's anyway even less possible to localize "particles" than within non-relativostic QM. The reason is that if you want to confine a "particle" to a small region in space you need pretty strong fields to do so and due to this interaction rather than confining the particle more to the small region you create more particles. That's why a single-particle picture is problematic in relativistic QT, because of the possibility that in interactions particles are destroyed and new ones created. That's described most naturally by a quantum field theory, and that's why relativistic QT is described as a quantum field theory.

Another advantage is that a field description of interactions is a local description, i.e., there is no need for instantaneous actions at a distance to describe the interaction between particles. That's the great achievement by Faraday and Maxwell which lead to the discovery of classical electrodynamics, and in 1905 it became clear that it is indeed a relativistic field theory, which can quantized to get Quantum Electrodynamics. This description also solves the notorious problem of causality, i.e., it enables a description where by construction no causality violations occur, i.e., there are no causal connections between space-like separated events, i.e., any interaction can act over a distance with a speed less than or equal the speed of light.

Thus the mathematical description leading to successful relativistic quantum-theoretical theories all hints at a field picture, and indeed it's much more natural to think of a photon as a certain state of the electromagnetic field, a single-photon Fock state since this is the, admittedly pretty abstract, description where the socalled "wave-particle duality" (a contradiction in itself!) of the old quantum theory is resolved into a consistent description. Particularly it describes both, the wave and the particle aspects, in the behavior of a single photon in a consistent way: On the one hand you have the interference effects leading to a double-slit diffraction pattern when collecting many equally prepared photons on the screen and on the other hand that each single photon can make only a single spot on the screen, i.e., it can be absorbed as a whole or it's not detected at all.

The prize the founding fathers of QT had to pay was that they had to introduce the probabilistic meaning of the quantum state, i.e., that even when the photon's state is as completely determined as one can observables don't take determined values but when measured you get a random result with probabilities described by the quantum state. E.g., you can't say where an individual photon will hit the screen when sent through the double slit but only the probability distribution for where it will be measured, and this probability distribution is observable only on an ensemble of equally prepared photons.
 
  • Like
Likes topsquark

FAQ: Why doesn't the detector affect the result?

Why is it important for the detector to not affect the result?

It is important for the detector to not affect the result because it can introduce errors or bias into the data. This can lead to inaccurate conclusions and hinder the progress of scientific research.

How can we ensure that the detector does not affect the result?

We can ensure that the detector does not affect the result by carefully calibrating and testing the detector before use, using appropriate shielding and filtering techniques, and implementing proper experimental controls.

Can the detector ever have an impact on the result?

While every effort is made to prevent the detector from affecting the result, there are certain scenarios where it may have a small impact. For example, in extremely sensitive experiments, the detector may introduce a small amount of noise. However, this impact is usually negligible and can be accounted for in data analysis.

How do we know if the detector is affecting the result?

We can determine if the detector is affecting the result by comparing the data obtained with and without the detector, or by conducting control experiments. If there is a significant difference in the results, it is likely that the detector is having an impact.

What steps can be taken to minimize the impact of the detector on the result?

To minimize the impact of the detector on the result, we can use advanced signal processing techniques, optimize experimental conditions, and use multiple detectors for cross-validation. It is also important to regularly calibrate and maintain the detector to ensure its accuracy and reliability.

Back
Top