- #1
maverick6664
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Reading back in my book, Greiner's "QM :an introduction" I found a formula I don't understand.
Let [tex]\alpha[/tex] be a real number, [tex]\Delta \hat{A}, \Delta \hat{B}[/tex] be Hermitian operators. Now I have
[tex]\int (\alpha \Delta \hat{A} - i \Delta \hat{B})^* \psi^* (\alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx
= \int \psi^* (\alpha \Delta \hat{A} + i \Delta \hat{B}) ( \alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx[/tex]
This leads to an expected result to prove Heisenberg's Uncertainty Relations, but I think the right-hand side of this formula should be
[tex]\int \psi^* (\alpha \Delta \hat{A}^* + i \Delta \hat{B}^*) (\alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx[/tex]
I should be wrong, but I don't know why. Operators [tex]\Delta \hat{A}, \Delta \hat{B}[/tex] can be complex... (or are they always real?) So will anyone tell me how or why it's correct?
Thanks in advance!
Let [tex]\alpha[/tex] be a real number, [tex]\Delta \hat{A}, \Delta \hat{B}[/tex] be Hermitian operators. Now I have
[tex]\int (\alpha \Delta \hat{A} - i \Delta \hat{B})^* \psi^* (\alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx
= \int \psi^* (\alpha \Delta \hat{A} + i \Delta \hat{B}) ( \alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx[/tex]
This leads to an expected result to prove Heisenberg's Uncertainty Relations, but I think the right-hand side of this formula should be
[tex]\int \psi^* (\alpha \Delta \hat{A}^* + i \Delta \hat{B}^*) (\alpha \Delta \hat{A} - i \Delta \hat{B}) \psi dx[/tex]
I should be wrong, but I don't know why. Operators [tex]\Delta \hat{A}, \Delta \hat{B}[/tex] can be complex... (or are they always real?) So will anyone tell me how or why it's correct?
Thanks in advance!
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