- #1
nycmathdad
- 74
- 0
Explain why the Intermediate Value Theorem gives no information about the zeros of the function
f(x) = ln(x^2 + 2) on the interval [−2, 2].
Let me see.
Let x = -2.
f(-2) = ln((-2)^2 + 2)
f(-2) = ln(4 + 2)
f(-2) = ln (6). This is a positive value.
When I let x be 2, I get the same answer.
So, f(-2) = f(2).
So, I conclude by saying that the Intermediate Value Theorem does not apply here because both answers are the same value and both are positive.
However, the textbook answer is different.
Textbook Answer:
"This does not contradict the IVT. f (−2) and f (2) are both positive, so there is no guarantee that the function has a zero in the interval (−2, 2)."
f(x) = ln(x^2 + 2) on the interval [−2, 2].
Let me see.
Let x = -2.
f(-2) = ln((-2)^2 + 2)
f(-2) = ln(4 + 2)
f(-2) = ln (6). This is a positive value.
When I let x be 2, I get the same answer.
So, f(-2) = f(2).
So, I conclude by saying that the Intermediate Value Theorem does not apply here because both answers are the same value and both are positive.
However, the textbook answer is different.
Textbook Answer:
"This does not contradict the IVT. f (−2) and f (2) are both positive, so there is no guarantee that the function has a zero in the interval (−2, 2)."