I think I got what you mean, but I would like to double check.Keith_McClary said:If it is a pure LC circuit (R=0) (or pure L or pure C) there will be no energy/power absorbed.
Thank you for confirming!Keith_McClary said:@hidemi Right.
The reason I*ε cannot be used to calculate power is because it is not a valid equation for power. The equation I*ε is used to calculate the voltage drop across a resistor, not the power dissipated by the resistor. To calculate power, you need to use the equation P=VI, where P is power, V is voltage, and I is current.
No, I*ε can only be used to calculate the voltage drop across a resistor. In other situations, such as in a circuit with capacitors or inductors, different equations must be used to calculate power.
If you use I*ε to calculate power, you will get an incorrect value. This is because the equation does not take into account the resistance of the circuit, which is necessary to accurately calculate power.
Yes, there are several other equations that can be used to calculate power depending on the specific situation. Some examples include P=I^2*R, P=V^2/R, and P=I^2*Rcosθ, where R is resistance and θ is the phase angle between voltage and current.
To calculate power accurately, you need to use the correct equation for the specific situation. It is important to understand the components and characteristics of the circuit in order to select the appropriate equation. It is also important to use accurate measurements for voltage, current, and resistance in the calculation.