Why is 3 = a x (1)^2 x (-3)^2 in this step of the solution?

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TheePhysicsStudent
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Homework Statement
I understand everything before and after this line but not sure how they actually came to that conclusion, many thanks.
Relevant Equations
ax^4 + bx^3 + cx^2 + dx + 3
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Because they stated that x=0, therefor a(x+1)^2 becomes a(0+1)^2 = a(1)^2 and (x-3)^2 becomes (0-3)^2 = (-3)^2.

Note that the values of x=0 and y=3 come directly from the graph. You can see that the function (the squiggly line on the graph) is at a y-value of 3 when it crosses the y-axis, which corresponds to an x-value of 0. Therefor x=0 and y=3, which you just plug into the equation.
 
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Ahhhh I see it now, many thanks!
 
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For those that are wondering why -1 and 3 are roots of multiplicity 2, it is because from the graph we can see that they are roots of y(x)=0 but also they are local minima hence also roots of y'(x)=0.
 

FAQ: Why is 3 = a x (1)^2 x (-3)^2 in this step of the solution?

Why is the equation 3 = a x (1)^2 x (-3)^2 used in this step of the solution?

This equation is used to demonstrate the relationship between the variables and constants in the context of the problem. It shows how the value of 3 is derived by multiplying the constant 'a' with the squared values of 1 and -3.

What does the variable 'a' represent in this equation?

The variable 'a' typically represents a constant or coefficient that needs to be determined. In this context, 'a' is a factor that, when multiplied by the other terms, results in the value of 3.

Why are the numbers 1 and -3 squared in this equation?

Squaring the numbers 1 and -3 is part of the mathematical operation needed to solve the equation. Squaring ensures that both numbers contribute positively to the product, as squaring a negative number results in a positive value.

Can you explain how 3 is derived from the equation?

Yes, the equation 3 = a x (1)^2 x (-3)^2 can be simplified as follows: (1)^2 is 1, and (-3)^2 is 9. Therefore, the equation becomes 3 = a x 1 x 9, which simplifies to 3 = 9a. Solving for 'a' gives a = 3/9 or a = 1/3.

Is this equation always valid for any value of 'a'?

No, the equation is only valid for the specific value of 'a' that satisfies it. In this case, 'a' must be 1/3 for the equation to hold true, as determined from the simplification process. For other values of 'a', the equation would not be valid.

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