Why Is an Apple Simply Connected but the Number 8 Multiply Connected?

[saravanan13]

Dear Friends

In the complex functions, I completely understand the simply connected region but not the multiply connected region?
An apple is a simply connected region but No. 8 is multiply connected. How?

 

[lavinia]

Dear Friends

In the complex functions, I completely understand the simply connected region but not the multiply connected region?
An apple is a simply connected region but No. 8 is multiply connected. How?

Simply connected means that every closed curve can be shrunk to a point. On the figure eight there are infinitely many curves that can not be shrunk to a point. Also on a circle.

A disk minus a point is not simply connected. For instance look at a branch of the logarithm in the unit disk minus the origin.

 

[saravanan13]

Simply connected means that every closed curve can be shrunk to a point. On the figure eight there are infinitely many curves that can not be shrunk to a point. Also on a circle.

A disk minus a point is not simply connected. For instance look at a branch of the logarithm in the unit disk minus the origin.

Thank
I could not follow your Second statement. Especially " branch of logarithm". Why can't a circle be simply connected?

 

[lavinia]

Thank
I could not follow your Second statement. Especially " branch of logarithm". Why can't a circle be simply connected?

The angle function on a circle is defined only locally but its exterior derivative is globally defined. Therefore it is a closed 1 form that is not the exterior derivative of a function.

The integral of the derivative of the complex logarithm around a circle centered at the origin is the same as the integral of the angle function.

Another way to look at this is - suppose the curve that loops around the circle once were null homotopic. Then there would be a map from a disk to the circle that was equal to this curve on the boundary of the disk. Stokes Theorem then tells you that the integral of the exterior derivative of the angle function over this loop must be zero. But the intergral is not zero. It is 2pi.

I suggest that you look at the covering space argument that also proves that the circle is not simply connected. This avoids homology and uses purely topological arguments.

Intuitively, a null homotopic loop on the circle would have to retrace its path and return to its end point in the opposite direction that it came in. The loop that goes around once does not do this.

 

[blue_raver22]

Hello,

I can help explain the concept of simply connected and multiply connected regions in complex functions. In mathematics, a simply connected curve is a curve that does not contain any holes or "islands." This means that any closed loop drawn on this curve can be continuously shrunk to a single point without leaving the curve. On the other hand, a multiply connected curve contains at least one hole or "island" and therefore cannot be continuously shrunk to a single point without leaving the curve.

To better understand this concept, let's use the examples you mentioned. An apple can be seen as a simply connected region because it does not have any holes or "islands" in its shape. However, the number 8 can be seen as a multiply connected region because it has two holes or "islands" in its shape. If you were to draw a closed loop around each of the holes in the number 8, you would not be able to shrink them to a single point without leaving the curve.

I hope this explanation helps clarify the difference between simply connected and multiply connected regions in complex functions. Let me know if you have any further questions.

Best regards,