- #1
chriswwt
- 5
- 0
Homework Statement
Explain why copper(II) is the more common oxidation state than copper (I) by giving the electronic configurations of the ions involved.
The Attempt at a Solution
i've considered about the configurations of Cu+ and Cu2+ but the result seems to contradict the fact.
Cu+:[Ar]3d^10
Cu2+:[ar]3d^9
Base on the configuration, Cu2+ should be readily reduced to Cu+,so Cu+ should be the more common oxidation state in this regard.
Please help correct mistakes I've make, or did i think in a wrong way?
thanks.