Why is my Atwood's Machine homework solution incorrect?

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In summary, the conversation was about a physics problem involving calculating the net force and tension on different blocks on a table. The equations used were Sigma F = ma and Fg = mg. The attempt at a solution involved assigning variables to the different blocks and using the equations to calculate the values. The final solutions for the net force and tension were 2.5 m/s^2 and -49 N, respectively. The conversation ended with the conclusion that the problem was solved.
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Homework Statement



ok here's the problem in a picture

h t t p : / / i m g 1 9 2 . i m a g e s h a c k . u s / i m g 1 9 2 / 4 5 0 0 / c a p t u r e x x w . j p g



Homework Equations



Sigma F = ma
Fg = mg

The Attempt at a Solution



ok I called the 4 kg block m3 and the 2 kg block m2 and the 1 kg block m1

I don't see what is wrong with my work

a. net force on m3 = m3 a = Fg3 - Fg2 - Fg1

divide by m3 to get a

a = (Fg3 - Fg2 - Fg1)/m3

made it look nice

a = (m3 g - m2 g - m1 g)/m3
= g - (m2g)/m3 - (m1 g)/m3
= g(1 - m2/m3 - m1/m3)
=9.8(1 - 2/4 - 1/4) = 2.5 m/s^2

b. net force on m3 = m3 a = Fg3 - Ft3
solved for the force of tension
Ft3 = -m3(a+g) = -4.0(2.5+9.8)= - 49 N

c. Net force m1 = m1 a = -Fg1 + Ft1
solved for Ft1
Ft1 = m1 (a+g) = 1.0(2.5 + 9.8) = 12 N
 
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i think i got it nevermind
 

FAQ: Why is my Atwood's Machine homework solution incorrect?

How does an Atwood's Machine work?

An Atwood's Machine is a simple physics experiment that demonstrates the principles of acceleration and force. It consists of two masses connected by a light string, with one mass hanging over a pulley. When one mass is released, it accelerates towards the ground due to the force of gravity, causing the other mass to rise. This creates a tension force in the string and results in the acceleration of both masses.

What is the equation for calculating acceleration in an Atwood's Machine?

The equation for calculating acceleration in an Atwood's Machine is a = (m1 - m2)g / (m1 + m2), where m1 and m2 are the masses on either side of the pulley and g is the acceleration due to gravity (9.8 m/s^2).

How does the mass of the pulley affect the acceleration in an Atwood's Machine?

The mass of the pulley does not affect the acceleration in an Atwood's Machine. This is because the pulley is considered to be a frictionless and massless object, so it does not contribute to the overall forces acting on the system.

What is the purpose of using an Atwood's Machine in physics experiments?

An Atwood's Machine is often used in physics experiments to study the principles of acceleration and force. It allows for the manipulation of various factors, such as mass and tension, to observe their effects on the acceleration of the system. It also provides a simple and visual way to demonstrate these concepts to students.

Are there any real-world applications of Atwood's Machine?

Yes, Atwood's Machine has several real-world applications. It is used in industries such as construction and transportation to lift heavy objects and control their speed and direction. It is also used in elevators and cranes to move loads vertically and horizontally. Additionally, the principles of Atwood's Machine are used in various machines and devices, such as bicycles and cars, to transfer and control forces.

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