Why Is My Calculation of the Center of Mass for a Uniform Wire Incorrect?

In summary, the problem involves finding the x coordinate of the center of mass point of a uniform wire with a circular arc of 22 degrees and a radius of 1m. The equation used is x = (2r/theta)*sin(theta/2) and the mistake was forgetting to convert theta to radians.
  • #1
toastie
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Homework Statement


Find x coordinant of the the center of mass point of a uniform wire that subtends an arc of 22 degrees if the radius of the circular arc is 1m.


Homework Equations


I begin with: length = r*theta

Therefore M = density*r*theta

dm = density*ds = denisty*r8*d(alpha)

x= (1/M)*[integral of r*cos(alpha)*denisty*r*d(alpha) from (theta/2) to -(theta/2)

Thus, I get
x = (2r/theta)*sin(theta/2)



The Attempt at a Solution


I keep getting an answer of 0.01735 m. However, the online homework is telling me that it is not the correct answer.

I am not sure where in the above calculations I would have messed up. Could someone please point out where I have made an error?

Thank you in advance.
 
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  • #2
okay nevermind I was forgetting to convert theta to radians.
 
  • #3




It seems like you have approached the problem correctly. However, the value of x that you have calculated may not be the exact solution because of rounding errors. I would suggest double-checking your calculations and rounding to more decimal places to get a more precise answer. Additionally, make sure that you are using the correct units for all your values, as that can also affect the final result. If you are still having trouble, it may be helpful to consult with a classmate or your instructor for further clarification. Keep up the good work!
 

FAQ: Why Is My Calculation of the Center of Mass for a Uniform Wire Incorrect?

What is the center of mass?

The center of mass is the point at which an object can be balanced or supported without any rotation occurring. It is the point where all of the mass of an object is evenly distributed.

How is the center of mass calculated?

The center of mass is calculated by finding the weighted average of the positions of all the particles that make up an object. This can be done by considering the mass of each particle and its distance from a chosen reference point.

Why is it important to find the center of mass?

Finding the center of mass is important because it helps us understand the stability and balance of an object. It is also essential in understanding the motion and behavior of objects, as the center of mass is the point around which an object will rotate.

Can the center of mass be outside of an object?

Yes, the center of mass can be outside of an object. This is possible when the object has an irregular shape or when the mass is not evenly distributed. However, the center of mass will always be located somewhere within the bounds of the object.

How can the center of mass be used in real-life applications?

The concept of center of mass is used in many real-life applications, such as in engineering and design to ensure stability and balance of structures. It is also used in sports, such as gymnastics and diving, to achieve perfect balance and control. In physics, the center of mass is crucial in understanding the movement and behavior of objects, such as in rocket launches and satellite orbits.

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