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Because that's how the metric is defined in an inertial frame in special relativity.BLevine1985 said:
No, because the diagram is not depicting a Euclidean geometry. It's depicting a Minkowskian geoemetry. That means you cannot interpret lines and angles in the diagram as if they were Euclidean; they aren't.BLevine1985 said:
You're welcome!BLevine1985 said:
The reason Tau-AB^2 is not equal to t^2 + x^2 is because they are different mathematical expressions. Tau-AB^2 represents the product of Tau and the square of AB, while t^2 + x^2 represents the sum of the squares of t and x. These two expressions have different operations and cannot be equated.
No, Tau-AB^2 and t^2 + x^2 cannot be simplified to be equal because they have different operations and cannot be combined or simplified using mathematical rules.
No, Tau-AB^2 and (Tau-A)(Tau-B)^2 are not the same. The first expression represents the product of Tau and the square of AB, while the second expression represents the product of Tau-A and the square of Tau-B. These are different expressions and cannot be equated.
Tau-AB^2 and Tau(A+B)^2 are not equal because they have different operations. The first expression represents the product of Tau and the square of AB, while the second expression represents the product of Tau and the square of (A+B). These operations are not equivalent and cannot be equated.
No, Tau-AB^2 and t^2 + x^2 cannot have the same value because they are different expressions with different operations. Even if the values of Tau, A, and B are the same, the two expressions will still have different values.
