Why is the change in y different than expected when using derivatives?

In summary, when you have a derivative, it is a rate of change that is only exact at that point. If you try to use that derivative to find other points on the curve it will fail as the deviation from your original x increases.
  • #1
Line
216
0
I'm trying to understand something. Derrivatives are basically the same as differentials. The both apply to the chnange in XY values.

Now I have an eqaition y=x*x x*x=x sqaured.

So that being here are my XY values

X y
_______
1 1
2 4
3 9
4 16
5 25


So that being dv=2x . But if you plug that in x the change is different.

WIth that eqauition if x=1 the change in y should be 2. So if x changes by 1. But is chnage x by 1 y becomes 4.

If x=2 the change in y should be 4. But if we change x by 1 y=9 not 8.

What's going on?
 
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  • #2
Because a derivative is an instantaneous rate of change, and changing x by 1 is a large enough change for the tangent line at the point to not be very close to the original function anymore.
 
  • #3
So what is the derivative for? You can't just plug it in at any point and get the change for y?
 
  • #4
Line said:
So what is the derivative for? You can't just plug it in at any point and get the change for y?

You can, BUT it is an instantaneous rate of change that is only exact at that point. If you try to use that derivative to find other points on the curve it will fail as the deviation from your original x increases, in other words let's say you have

y = f(x)

then
y' = f'(x)

and the differential is

dy = f'(x)dx

this allows you to approximate the original function by knowing its derivative and an initial point. But the further you go from the initial point, as dx increases, the approximation will become less valid because a derivative is an instantaneous rate of change and will be exact only at that point.
 
  • #5
So that being here are my XY values

X y
_______
1 1
2 4
3 9
4 16
5 25


So that being dv=2x . But if you plug that in x the change is different.

WIth that eqauition if x=1 the change in y should be 2. So if x changes by 1. But is chnage x by 1 y becomes 4.

If x=2 the change in y should be 4. But if we change x by 1 y=9 not 8.

What's going on?
Let's experiment! What if, instead of increasing all of your x's by 1, you increased them by 0.1? So your table would look like:


X y
_______
1 ?
1.1 ?
1.2 ?
1.3 ?
1.4 ?


What if you did it by 0.01?


How do the results compare to the definition of a derivative? (You know, that stuff with limits!)

p.s. if y = x², then dy = 2x dx. (Of course, y' = 2x)
 

FAQ: Why is the change in y different than expected when using derivatives?

Why do we use derivatives to calculate changes in y?

Derivatives are used to calculate changes in y because they represent the instantaneous rate of change of a function at a specific point. This means that they can accurately measure and predict the change in y over small intervals, making them useful in a variety of scientific and mathematical applications.

What factors can affect the accuracy of the change in y calculated using derivatives?

There are several factors that can affect the accuracy of the change in y calculated using derivatives. These include errors in measurement or data, the complexity of the function being analyzed, and the chosen interval size for calculating the derivative.

Why might the change in y be different than expected when using derivatives?

The change in y may be different than expected when using derivatives due to the presence of outliers or noise in the data, as well as the limitations of the derivative function itself. Additionally, any assumptions made in the calculation or model being used may also contribute to the discrepancy.

How can we ensure the accuracy of the change in y calculated using derivatives?

To ensure the accuracy of the change in y calculated using derivatives, it is important to carefully select and clean the data being used, as well as consider the complexity of the function and the chosen interval size. It may also be helpful to compare the results to other methods of calculating the change in y, such as using numerical approximations or alternative mathematical models.

What are some real-world applications of using derivatives to calculate changes in y?

There are many real-world applications of using derivatives to calculate changes in y. Some examples include predicting stock market trends, analyzing the trajectory of moving objects, and determining the rate of change in chemical reactions. Derivatives are also widely used in fields such as engineering, physics, economics, and finance.

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