- #1
elitewarr
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For a question like In an experiment, the external diameter D and internal diameter d of a metal tube were found to be (64 +/- 2) mm and (47 +/- 1) mm respectively. What is the maximum percentage error for the cross-sectional area of the metal tube?
I will need to find the external area.
So, area = pi(1/2d)^2
But I'm confused over whether should the uncertainty change?
What I mean was 1/2(64 +/- 2) = (32 +/- 1) ??
Or will the uncertainty remain at 2? If it remains at 2, the percentage uncertainty will definitely change.
And why does the formula R=kAB, k is a constant and A and B are physical terms, has the uncertainty formula tR / R = tA / A + tB / B
where tR / R, tA / A, tB / B are fractional uncertainty.
Why is the constant excluded?
R = kAB = AB + AB + AB ... + AB
So won't the uncertainty add up?
Thanks.
I will need to find the external area.
So, area = pi(1/2d)^2
But I'm confused over whether should the uncertainty change?
What I mean was 1/2(64 +/- 2) = (32 +/- 1) ??
Or will the uncertainty remain at 2? If it remains at 2, the percentage uncertainty will definitely change.
And why does the formula R=kAB, k is a constant and A and B are physical terms, has the uncertainty formula tR / R = tA / A + tB / B
where tR / R, tA / A, tB / B are fractional uncertainty.
Why is the constant excluded?
R = kAB = AB + AB + AB ... + AB
So won't the uncertainty add up?
Thanks.