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erocored
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If the current goes through the first end of the resistor will it be less than on the other end of resistor?
No. Charge is conserved so that would lead to enormous charge accumulation in the resistor.erocored said:If the current goes through the first end of the resistor will it be less than on the other end of resistor?
Current is the amount of charge passing a point in unit time. That means it's the number of electrons passing a point in unit time multiplied by the charge on an electron. So if the current is different electrons must be stopping somewhere and accumulating - which would lead to a charge buildup which we don't see in practice. So the current must be the same.erocored said:If the current goes through the first end of the resistor will it be less than on the other end of resistor?
Just to add to the other replies, the Current is the same through the resistor, but the Voltage drops as the current flows through the resistor. The Voltage drop across a resistor as a Current I flows through it is given by the famous Ohm's Law equation: ##V = IR##.erocored said:If the current goes through the first end of the resistor will it be less than on the other end of resistor?
Don't worry if you don't understand this yet. It isn't necessary for students learning basic electronics. You'll get to this later, if you keep studying physics/electronics.etotheipi said:If you want the fancy-schmancy version of what was said above, you can construct a (mathematical) closed surface ##\Sigma## around the entire resistor, and then apply the continuity equation ##\frac{\partial \rho}{\partial t} + \nabla \cdot \vec{j} = 0##, i.e.$$\dot{Q} = -\int_{\Sigma} \vec{j} \cdot d\vec{S} = I_{\text{in}} - I_{\text{out}}$$In a steady state ##Q = \text{constant}## within that closed surface, so ##\dot{Q} = 0## and ##I_{\text{in}} = I_{\text{out}}##
If that were true then where would all those surplus electrons go? (I do love a noddy answer then one is available.)erocored said:If the current goes through the first end of the resistor will it be less than on the other end of resistor?
They could, of course, pile up in the resistor. But like charges repel. If the electrons build up in the resistor, only so many can be added before the repulsion becomes too significant and fewer start arriving.sophiecentaur said:If that were true then where would all those surplus electrons go? (I do love a noddy answer then one is available.)
erocored said:If the current goes through the first end of the resistor will it be less than on the other end of resistor?
In a series circuit, the current has only one path to flow through. This means that the same amount of current must pass through each component in the circuit. Since the current is not divided or split, it remains the same throughout the circuit.
The current in a series circuit stays constant due to the principle of conservation of charge. This means that the amount of charge entering a circuit must be equal to the amount of charge leaving the circuit. In a series circuit, the current is the rate of flow of charge, so it remains constant throughout the circuit.
No, the current in a series circuit cannot change as long as the circuit remains in the same state. This is because the amount of current is determined by the amount of voltage and resistance in the circuit, and these values do not change in a series circuit.
In a series circuit, the current and voltage are directly proportional. This means that as the current increases, the voltage also increases, and vice versa. This relationship is described by Ohm's Law, which states that voltage is equal to the current multiplied by the resistance.
Understanding the concept of constant current in series circuits is important because it allows us to predict and control the behavior of the circuit. By knowing that the current will remain the same throughout the circuit, we can calculate the voltage and resistance needed for different components and ensure that the circuit functions properly.