- #1
kended
- 10
- 0
Hello everyone,
Could someone explain or direct me to some detailed explanations as to why is the electric field at a conductor greatest where the curvature is sharpest?
I just can't seem to grasp this concept. I understand sharp edges do have this property so is this that there is more charge density at those points? And if so, what would prevent another point close by (on a rounded surface) to have the same charge density given that both points are at the same KV potential?
In another words, how is a sharp edge (high curvature) affecting the local charge distribution at an atomic level?
Thanks for enlightening me :)
Regards
Could someone explain or direct me to some detailed explanations as to why is the electric field at a conductor greatest where the curvature is sharpest?
I just can't seem to grasp this concept. I understand sharp edges do have this property so is this that there is more charge density at those points? And if so, what would prevent another point close by (on a rounded surface) to have the same charge density given that both points are at the same KV potential?
In another words, how is a sharp edge (high curvature) affecting the local charge distribution at an atomic level?
Thanks for enlightening me :)
Regards