- #1
s3a
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Homework Statement
The problem along with its solution are attached in TheProblemAsWellAsSolution.jpeg file. For this post, I'm only referring to part (a), since part (b) is the same thing with another number.
Homework Equations
V = IR
Parallel circuit: ##I = I_1 + I_2 + . . . + I_n##
The Attempt at a Solution
I understand how to get i = 4##i_x## - 4.0, and I understand that multiplying both sides of that equation by R = 10 Ω gives iR = 40##i_x − 40.0, but when looking at the circuit, I'm confused as to why ν_R = 40.0 V instead of −40.0 V. I thought that when (positive) current goes from the positive to negative end of a resistor, that there is a voltage drop, as the following website implies.: http://faculty.wwu.edu/vawter/PhysicsNet/Topics/DC-Current/DropGain.html
Could someone please clarify this for me?
Any input would be GREATLY appreciated!
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