Why is |X+Y|<|X|+|Y|? Exploring Spivak's Proof

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In summary, the conversation discusses two inequalities related to vectors X and Y in a n dimensional real space. The first inequality, known as the triangle inequality, states that the length of the vector X+Y cannot be larger than the sum of the lengths of X and Y. The second inequality, known as the law of cosines, states that the product of the lengths of X and Y multiplied by the cosine of the angle between them is smaller than or equal to the product of the lengths of X and Y. These inequalities are important in understanding the relationship between vector lengths and inner products.
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Suppose you had two vectors X and Y which are elements in in a n dimensional real space. Now why is |X+Y|<|X|+|Y|, I've been trying to understand spivak's proof but it boils down to why is |X||Y|>sum of(xy) where xy is the product of the individual components...
 
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If the norm is derived from an inner product (as, it would appear, in your case), there is the following standard geometric argument for the latter inequality.

Consider the following self-evident fact: [tex]\Vert x + ty \Vert^2 \ge 0[/tex], where [tex]t[/tex] is a parameter. Now, the left-hand side is a quadratic function in [tex]t[/tex], i.e. a parabola, but the inequality says that this parabola has to lie above the x-axis (with at most one real zero).
(If it were to have two real zeros, there would be a distinct interval where the parabola would go below zero, thus contradicting our initial inequality).

The determinant of the quadratic function above is just [tex]\left<x, y\right>^2 - \left\Vert x \right\Vert^2 \left\Vert y \right\Vert^2[/tex], and expressing the fact that the parabola has no two distinct zeros is done by saying that this determinant should be smaller than or equal to zero, which is the inequality you need.
 
  • #3
but the first ineqality is the rather obvious "triangle inequality", that says one side, namely X+Y, of a triangle cannot be longer than the sum of the lengths of the other two sides, namely X and Y.

the second inequality is also easily seen from the law of cosines, that says

X.Y = |X||Y|cos(t) where t is now the angle between the vectors X and Y. Thus obviously (since cos is never greater than 1), we have
|X.Y|≤ |X||Y|.
 
  • #4
True, but (1) try giving a sound proof for the triangle inequality, and (2) the law of cosines is usually a consequence of the triangle inequality: i.e. one defines the angle between two vectors as the arccos of X.Y / |X||Y| (which is smaller than one and hence in the domain of arccos).
 
  • #5
You can prove the law of cosines quite simply by using a little geometry: it is just the cosine rule for triangles.
 

FAQ: Why is |X+Y|<|X|+|Y|? Exploring Spivak's Proof

What is the significance of the inequality |X+Y|<|X|+|Y|?

The inequality |X+Y|<|X|+|Y| is significant because it is a fundamental property of absolute values and has important applications in various fields of mathematics, such as algebra, calculus, and geometry. It also plays a crucial role in Spivak's proof of the triangle inequality.

How is the inequality |X+Y|<|X|+|Y| related to the triangle inequality?

The triangle inequality states that the sum of two sides of a triangle must be greater than the third side. The inequality |X+Y|<|X|+|Y| is a special case of the triangle inequality, where X and Y represent the sides of a triangle. This connection is the basis of Spivak's proof.

What is Spivak's proof of the inequality |X+Y|<|X|+|Y|?

Spivak's proof uses the properties of absolute values and the triangle inequality to show that |X+Y|<|X|+|Y|. It involves breaking down the absolute values into different cases and using algebraic manipulations to arrive at the desired inequality. It is a concise and elegant proof that highlights the importance of understanding absolute values and their properties.

Why is Spivak's proof of |X+Y|<|X|+|Y| considered a fundamental proof in mathematics?

Spivak's proof is considered fundamental because it demonstrates the power and versatility of absolute values and their properties. It also highlights the importance of understanding and applying fundamental concepts in mathematics, such as the triangle inequality. This proof has applications in various areas of mathematics, making it an essential tool for any mathematician.

Are there any real-life applications of the inequality |X+Y|<|X|+|Y|?

Yes, there are many real-life applications of this inequality, especially in fields such as physics, engineering, and economics. For example, in physics, this inequality is used to determine the maximum error in measurements, while in economics, it is used to represent budget constraints. It also has applications in computer science, such as in the design of algorithms and data compression techniques.

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