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amgc63
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- TL;DR Summary
- Question;
Given that a dipole antenna has directional gain of 2, calculate the power gain in Dbi?
Answer;
Power gain = 10 log (x/y), where y =1
Power gain = 10 log (2/1) = 3dbi
My question is….how come y = 1??
Thanks in advance
Question;
Given that a dipole antenna has directional gain of 2, calculate the power gain in Dbi?
Answer;
Power gain = 10 log (x/y), where y =1
Power gain = 10 log (2/1) = 3dbi
My question is….how come y = 1??
Thanks in advance
Given that a dipole antenna has directional gain of 2, calculate the power gain in Dbi?
Answer;
Power gain = 10 log (x/y), where y =1
Power gain = 10 log (2/1) = 3dbi
My question is….how come y = 1??
Thanks in advance